• LeetCode 202. Happy Number (快乐数字)


    Write an algorithm to determine if a number is "happy".

    A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

    Example: 19 is a happy number

    • 12 + 92 = 82
    • 82 + 22 = 68
    • 62 + 82 = 100
    • 12 + 02 + 02 = 1

     题目标签:Hash Table

      题目给了我们一个数字,让我们判断它是不是 Happy Number。

      Happy Number 最终会变成1,很好判断;Non-Happy Number 最后会无限循环在一个cycle。

      所以,我们要解决如何判断 一个数字是否在一个无限循环里,可以建立HashSet 记录它每一次的变化数字,一旦它重复了,说明,它在循环。

    Java Solution:

    Runtime beats 61.14% 

    完成日期:05/16/2017

    关键词:HashSet

    关键点:利用HashSet 记录每一个数字

     1 class Solution 
     2 {
     3     public boolean isHappy(int n) 
     4     {
     5         HashSet<Integer> set = new HashSet<>();
     6         
     7         while(n != 1) // happy number will get out of this loop
     8         {
     9             if(set.contains(n)) // if a number repeats in a cycle, return false;
    10                 return false;
    11             
    12             set.add(n);
    13             
    14             int sum = 0;
    15             
    16             while(n != 0) // get each digit from number
    17             {
    18                 int digit = n % 10;
    19                 
    20                 sum += digit * digit;
    21                 n = n / 10;
    22             }
    23             
    24             n = sum; // update n with new number
    25         }
    26         
    27         return true;
    28     }
    29 }

    参考资料:N/A

    LeetCode 题目列表 - LeetCode Questions List

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  • 原文地址:https://www.cnblogs.com/jimmycheng/p/7734854.html
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