用户请求url:http://localhost:8000/getconfig?v=1.03.01,根据参数v=1.03.01或者其他的值返回不同的json值。如果用户请求不带该参数,则返回默认的json值。
下面是nginx.conf的配置:
server { listen 8000; server_name localhost; #charset koi8-r; #access_log logs/host.access.log main; location ~ ^/getconfig { default_type application/json; if ( $query_string ~* ^(.*)v=1.03.01$ ){ return 200 '{"status": "0","message": "OK","body": {"api":"http://116.62.113.124:8080/basestock000/","h5":"http://118.31.69.127:8090/","phone":"4000670019","cr":"Copyright xxxxx"}}'; } return 200 '{"status": "0","message": "OK","body": {"api":"http://116.62.113.124:8080/basestock000/","h5":"http://118.31.69.127:8090/","phone":"4000670019","cr":"Copyright xxxxx"}}'; } }
用户请求http://localhost:8000/getconfig时,应该返回
return 200 '{"status": "0","message": "OK","body": {"api":"http://116.62.113.124:8080/basestock000/","h5":"http://118.31.69.127:8090/","phone":"4000670019","cr":"Copyright xxxxx"}}';
浏览器模拟请求:http://localhost:8000/getconfig
浏览器请求:http://localhost:8000/getconfig?v=1.03.01时:
可以满足需求,当有多个参数值的时候,本人没有想出来别的更好的办法,本来以为可以使用if else或者if else if的,结果我在测试的时候配置检查都不通过,没办法就采用了下面的办法:
server { listen 8000; server_name localhost; #charset koi8-r; #access_log logs/host.access.log main; location ~ ^/getconfig { default_type application/json; if ( $query_string ~* ^(.*)v=1.03.01$ ){ return 200 '{"status": "0","message": "OK","body": {"api":"http://116.62.113.124:8080/basestock000/","h5":"http://118.31.69.127:8090/","phone":"4000670019","cr":"Copyright xxxxx"}}'; } if ( $query_string ~* ^(.*)v=1.03.02$ ){ return 200 '{"status": "0","message": "OK","body": {"api":"http://116.62.113.124:8080/basestock122/","h5":"http://118.31.69.127:8092/","phone":"40006700191222","cr":"Copyright xxxxx1222"}}'; } return 200 '{"status": "0","message": "OK","body": {"api":"http://116.62.113.124:8080/basestock000/","h5":"http://118.31.69.127:8090/","phone":"4000670019","cr":"Copyright xxxxx"}}'; } }
请求http://localhost:8000/getconfig?v=1.03.02:
虽然也可以达到目的,但是感觉特别low,希望哪位大神有别的比较高端的解决方法可以指导一下 ^=^!