• 2020年3月16日python学习笔记——详细列表解说


    坚持+思考+输出

    1、学习方式:查看提供视频(30分钟)+自我整理笔记(2小时)+周末视频输出

    2、笔记方式按提问方式整理。

    # name = ["like","love","love","good"]
    # n2 = ["test","hebing"]
    #print(dir(name))
    #  'append', 'clear', 'copy', 'count', 'extend', 'index', 'insert', 'pop', 'remove', 'reverse', 'sort'
    
    #列表的增加操作
    # name.append("插入最后")   #添加到最后
    # print(name)
    #
    # name.insert(1,"插入指定位置")
    # print(name)
    #
    # name.extend(n2)#把n2插入到name列表里面
    # print(name)
    #
    # name.insert(2,[1,2,3]) #列表嵌套
    # print(name)
    
    
    name = ["like","love","love","good"]
    # n2 = ["test","hebing"]
    #删除
    # del name[0]  #删除指定元素
    # print(name)
    #
    # name.pop()  #默认删除最后一个元素并返回被删除的值
    # print(name)
    #
    # name.pop(1)#删除指定元素
    # print(name)
    #
    # n2.clear() #直接删除
    # print(n2)
    name.remove("like")  #直接移出元素
    print(name)
    
    # 查操作
    # name = ["like","love","love","good","like"]
    # n2 = ["test","hebing"]
    #
    # print(name.index("love"))#返回从左开始匹配到的第一个like的索引
    #
    # print(name.count("like")) #返回like的个数
    
    #切片
    # name = ["like","love","love","good","like"]
    # n2 = ["test","hebing"]
    #
    # print(name[1:7])# 切片的特性是顾头不顾尾,即start的元素会被包含,end-1是实际取出来的值
    #
    # print(name[1:7:2])# 步长, 允许跳着取值
    #
    # print(name[::-1])#通过把步长设置成负值,可达到列表返转的效果['like', 'good', 'love', 'love', 'like']
    
    # 排序&反转
    # 排序
    a = [83,4,2,4,6,19,33,21]  #从小到大进行排序
    # a.sort()
    # print(a)
    
    # 反转
    # a.reverse()
    # print(a)
    # print(a[::-1])
    
    
    # 循环列表
    name = ["like","love","love","good","like"]
    for i in name:
        print(i)
    

      

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  • 原文地址:https://www.cnblogs.com/jianchixuexu/p/12506464.html
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