• oracle plsql练习题-考核题


    数据库脚本:

    – Create table 学生信息
    create table HAND_STUDENT
    (
    STUDENT_NO VARCHAR2(10) not null,
    STUDENT_NAME VARCHAR2(20),
    STUDENT_AGE NUMBER(2),
    STUDENT_GENDER VARCHAR2(5)
    );
    – Add comments to the table
    comment on table HAND_STUDENT
    is ‘学生信息表’;
    – Add comments to the columns
    comment on column HAND_STUDENT.STUDENT_NO
    is ‘学号’;
    comment on column HAND_STUDENT.STUDENT_NAME
    is ‘姓名’;
    comment on column HAND_STUDENT.STUDENT_AGE
    is ‘年龄’;
    comment on column HAND_STUDENT.STUDENT_GENDER
    is ‘性别’;
    – Create/Recreate primary, unique and foreign key constraints
    alter table HAND_STUDENT add primary key (STUDENT_NO);

    – Create table 教师信息表
    create table HAND_TEACHER
    (
    TEACHER_NO VARCHAR2(10) not null,
    TEACHER_NAME VARCHAR2(20),
    MANAGER_NO VARCHAR2(10)
    );
    – Add comments to the table
    comment on table HAND_TEACHER
    is ‘教师信息表’;
    – Add comments to the columns
    comment on column HAND_TEACHER.TEACHER_NO
    is ‘教师编号’;
    comment on column HAND_TEACHER.TEACHER_NAME
    is ‘教师名称’;
    comment on column HAND_TEACHER.MANAGER_NO
    is ‘上级编号’;
    – Create/Recreate primary, unique and foreign key constraints
    alter table HAND_TEACHER add primary key (TEACHER_NO);

    – Create table 课程信息表
    create table HAND_COURSE
    (
    COURSE_NO VARCHAR2(10) not null,
    COURSE_NAME VARCHAR2(20),
    TEACHER_NO VARCHAR2(20) not null
    );
    – Add comments to the table
    comment on table HAND_COURSE
    is ‘课程信息表’;
    – Add comments to the columns
    comment on column HAND_COURSE.COURSE_NO
    is ‘课程号’;
    comment on column HAND_COURSE.COURSE_NAME
    is ‘课程名称’;
    comment on column HAND_COURSE.TEACHER_NO
    is ‘教师编号’;
    – Create/Recreate primary, unique and foreign key constraints
    alter table HAND_COURSE add constraint PK_COURSE primary key (COURSE_NO, TEACHER_NO);

    – Create table 成绩信息表
    create table HAND_STUDENT_CORE
    (
    STUDENT_NO VARCHAR2(10) not null,
    COURSE_NO VARCHAR2(10) not null,
    CORE NUMBER(4,2)
    );
    – Add comments to the table
    comment on table HAND_STUDENT_CORE
    is ‘学生成绩表’;
    – Add comments to the columns
    comment on column HAND_STUDENT_CORE.STUDENT_NO
    is ‘学号’;
    comment on column HAND_STUDENT_CORE.COURSE_NO
    is ‘课程号’;
    comment on column HAND_STUDENT_CORE.CORE
    is ‘分数’;
    – Create/Recreate primary, unique and foreign key constraints
    alter table HAND_STUDENT_CORE add constraint PK_SC primary key (STUDENT_NO, COURSE_NO);

    /*初始化学生表的数据**/
    insert into HAND_STUDENT values (‘s001’,’张三’,23,’男’);
    insert into HAND_STUDENT values (‘s002’,’李四’,23,’男’);
    insert into HAND_STUDENT values (‘s003’,’吴鹏’,25,’男’);
    insert into HAND_STUDENT values (‘s004’,’琴沁’,20,’女’);
    insert into HAND_STUDENT values (‘s005’,’王丽’,20,’女’);
    insert into HAND_STUDENT values (‘s006’,’李波’,21,’男’);
    insert into HAND_STUDENT values (‘s007’,’刘玉’,21,’男’);
    insert into HAND_STUDENT values (‘s008’,’萧蓉’,21,’女’);
    insert into HAND_STUDENT values (‘s009’,’陈萧晓’,23,’女’);
    insert into HAND_STUDENT values (‘s010’,’陈美’,22,’女’);
    commit;
    /********初始化教师表*************/
    insert into HAND_TEACHER values (‘t001’, ‘刘阳’,”);
    insert into HAND_TEACHER values (‘t002’, ‘谌燕’,’t001’);
    insert into HAND_TEACHER values (‘t003’, ‘胡明星’,’t002’);
    commit;
    /*****初始化课程表******************/
    insert into HAND_COURSE values (‘c001’,’J2SE’,’t002’);
    insert into HAND_COURSE values (‘c002’,’Java Web’,’t002’);
    insert into HAND_COURSE values (‘c003’,’SSH’,’t001’);
    insert into HAND_COURSE values (‘c004’,’Oracle’,’t001’);
    insert into HAND_COURSE values (‘c005’,’SQL SERVER 2005’,’t003’);
    insert into HAND_COURSE values (‘c006’,’C#’,’t003’);
    insert into HAND_COURSE values (‘c007’,’JavaScript’,’t002’);
    insert into HAND_COURSE values (‘c008’,’DIV+CSS’,’t001’);
    insert into HAND_COURSE values (‘c009’,’PHP’,’t003’);
    insert into HAND_COURSE values (‘c010’,’EJB3.0’,’t002’);
    commit;
    /*****初始化成绩表*************/
    insert into HAND_STUDENT_CORE values (‘s001’,’c001’,58.9);
    insert into HAND_STUDENT_CORE values (‘s002’,’c001’,80.9);
    insert into HAND_STUDENT_CORE values (‘s003’,’c001’,81.9);
    insert into HAND_STUDENT_CORE values (‘s004’,’c001’,60.9);
    insert into HAND_STUDENT_CORE values (‘s001’,’c002’,82.9);
    insert into HAND_STUDENT_CORE values (‘s002’,’c002’,72.9);
    insert into HAND_STUDENT_CORE values (‘s003’,’c002’,81.9);
    insert into HAND_STUDENT_CORE values (‘s001’,’c003’,’59’);
    commit;

    1.查询没学过“谌燕”老师课的同学,显示(学号、姓名)

    select out_stu.student_no, out_stu.student_name from hand_student
    out_stu where out_stu.student_no not in
    (select distinct hs.student_no
    from hand_course c,
    hand_teacher t,
    hand_student hs,
    hand_student_core hsc
    where c.teacher_no = t.teacher_no
    and hs.student_no = hsc.student_no
    and hsc.course_no = c.course_no
    and t.teacher_name = ‘谌燕’)

    SELECT hs.student_no, hs.student_name FROM hand_student hs WHERE
    NOT EXISTS (SELECT 1
    FROM hand_course hc,
    hand_teacher ht,
    hand_student_core hsc
    WHERE hc.teacher_no = ht.teacher_no
    AND hc.course_no = hsc.course_no
    AND ht.teacher_name = ‘谌燕’
    AND hsc.student_no = hs.student_no);

    2.查询没有学全所有课的同学,显示(学号、姓名)

    select hs.student_no, hs.student_name from hand_student hs,
    hand_student_core hsc where hs.student_no = hsc.student_no(+) group
    by hs.student_no, hs.student_name having count(hsc.course_no) <
    (select count(*) from hand_course c);

    3.查询 c001 课程比 c002 课程成绩高的所有学生,显示:学号,姓名

    select stu.student_no,stu.student_name from hand_student stu,
    (select t1.student_no
    from (select *
    from hand_student_core sc
    where sc.course_no = ‘c001’) t1,
    (select *
    from hand_student_core sc
    where sc.course_no = ‘c002’) t2
    where t1.student_no = t2.student_no
    and t1.core > t2.core) tt where stu.student_no = tt.student_no

    4.按各科平均成绩和及格率的百分数,按及格率高到低的顺序排序,显示(课程号、平均分、及格率)

    select hsc.course_no,
    avg(hsc.core),
    sum(case
    when hsc.core > 60 then
    1
    else
    0
    end) / count() 100 || ‘%’ pass_rate from hand_student_core hsc group by hsc.course_no order by
    to_number(substr(pass_rate, 1, length(pass_rate) - 1)) desc

    5.1992年之后出生的学生名单找出年龄最大和最小的同学,显示(学号、姓名、年龄)

    SELECT hs.student_no, hs.student_name, hs.student_age FROM
    hand_student hs,
    (SELECT MAX(hs.student_age) max_age, MIN(hs.student_age) min_age
    FROM hand_student hs
    WHERE to_number(to_char(SYSDATE, ‘yyyy’)) - hs.student_age > 1992) hh WHERE hs.student_age = hh.max_age
    OR hs.student_age = hh.min_age;

    6.列出矩阵类型各分数段人数,横轴为分数段[100-85]、[85-70]、[70-60]、[<60],纵轴为课程号、课程名称(提示使用case when句式)

    SELECT hsc.course_no,
    hc.course_name,
    SUM(CASE
    WHEN hsc.core BETWEEN 85 AND 100 THEN
    1
    ELSE
    0
    END) AS “[100-85]”,
    SUM(CASE
    WHEN hsc.core BETWEEN 70 AND 85 THEN
    1
    ELSE
    0
    END) AS “[85-70]”,
    SUM(CASE
    WHEN hsc.core BETWEEN 60 AND 70 THEN
    1
    ELSE
    0
    END) AS “[70-60]”,
    SUM(CASE
    WHEN hsc.core < 60 then
    1
    ELSE
    0
    END) AS “[<60]” FROM hand_student_core hsc, hand_course hc WHERE hsc.course_no = hc.course_no GROUP BY hsc.course_no,
    hc.course_name;

    7.查询各科成绩前三名的记录:(不考虑成绩并列情况),显示(学号、课程号、分数)

    SELECT student_no, course_no, core FROM (SELECT hsc.student_no,
    hsc.course_no,
    hsc.core,
    DENSE_RANK() OVER(PARTITION BY hsc.course_no ORDER BY hsc.core DESC) ranks
    FROM hand_student_core hsc) WHERE ranks < 4;

    8.查询选修“谌燕”老师所授课程的学生中每科成绩最高的学生,显示(学号、姓名、课程名称、成绩)

    SELECT hs.student_no,
    hs.student_name,
    hc.course_name,
    hsc.core FROM hand_student hs,
    hand_student_core hsc,
    hand_course hc,
    hand_teacher ht WHERE hs.student_no = hsc.student_no AND hsc.course_no = hc.course_no AND hc.teacher_no = ht.teacher_no
    AND ht.teacher_name = ‘谌燕’ AND hsc.core = (SELECT MAX(sc.core)
    FROM hand_student_core sc
    WHERE sc.course_no = hc.course_no);

    9.查询两门以上不及格课程的同学及平均成绩,显示(学号、姓名、平均成绩(保留两位小数))

    SELECT hsc.student_no,
    hs.student_name,
    ROUND(AVG(hsc.core),2) avg_core FROM hand_student_core hsc,
    hand_student hs WHERE EXISTS (SELECT sc.student_no
    FROM hand_student_core sc
    WHERE sc.core < 60
    AND sc.student_no = hsc.student_no
    GROUP BY sc.student_no
    HAVING COUNT(sc.student_no) > 1) AND hsc.student_no = hs.student_no GROUP BY hsc.student_no,hs.student_name;

    10。查询姓氏数量最多的学生名单,显示(学号、姓名、人数)

    SELECT hs.student_no, hs.student_name, ht.cnt FROM (SELECT
    SUBSTR(hs.student_name, 1, 1) surname,
    COUNT(1) cnt,
    dense_rank() OVER(ORDER BY COUNT(1) DESC) ranks
    FROM hand_student hs
    GROUP BY SUBSTR(hs.student_name, 1, 1)) ht,
    hand_student hs WHERE SUBSTR(hs.student_name, 1, 1) = ht.surname AND ht.ranks = 1;

    11.查询课程名称为“J2SE”的学生成绩信息,90以上为“优秀”、80-90为“良好”、60-80为“及格”、60分以下为“不及格”,显示(学号、姓名、课程名称、成绩、等级)

    SELECT hsc.student_no,
    hs.student_name,
    hc.course_name,
    hsc.core,
    CASE
    WHEN hsc.core >= 90 THEN
    ‘优秀’
    WHEN hsc.core < 90 AND hsc.core >= 80 THEN
    ‘良好’
    WHEN hsc.core < 80 AND hsc.core >= 60 THEN
    ‘及格’
    WHEN hsc.core < 60 THEN
    ‘不及格’
    END core_level FROM hand_student_core hsc,
    hand_course hc, hand_student hs WHERE hsc.co

    urse_no = hc.course_no AND hsc.student_no = hs.student_no AND
    hc.course_name = ‘J2SE’;

    12.这是一个树结构,查询教师“胡明星”的所有主管及姓名:(无主管的教师也需要显示),显示(教师编号、教师名称、主管编号、主管名称)

    select t.teacher_no,t.teacher_name,t.manager_no ,t2.teacher_name
    manager_name from hand_teacher t,hand_teacher t2 where t.manager_no =
    t2.teacher_no( start with t.teacher_name=’胡明星’ connect by prior
    t.manager_no=t.teacher_no

    13.查询分数高于课程“J2SE”中所有学生成绩的学生课程信息,显示(学号,姓名,课程名称、分数)

    SELECT hsc.student_no, hs.student_name, hc.course_name, hsc.core
    FROM hand_student_core hsc, hand_course hc, hand_student hs WHERE
    hsc.course_no = hc.course_no AND hsc.student_no = hs.student_no
    AND hsc.core > ALL (SELECT hsc.core
    FROM hand_student_core hsc, hand_course hc
    WHERE hsc.course_no = hc.course_no
    AND hc.course_name = ‘J2SE’) AND hc.course_name != ‘J2SE’;

    14.分别根据教师、课程、教师和课程三个条件统计选课的学生数量:(使用rollup),显示(教师名称、课程名称、选课数量)

    SELECT ht.teacher_name, hc.course_name, COUNT(1) nums FROM
    hand_student_core hsc, hand_teacher ht, hand_course hc WHERE
    hsc.course_no = hc.course_no AND hc.teacher_no = ht.teacher_no GROUP
    BY ROLLUP(ht.teacher_name,hc.course_name);

    15.查询所有课程成绩前三名的按照升序排在最开头,其余数据排序保持默认,显示(学号、成绩)

    SELECT hs.student_no, hs.core FROM (SELECT rownum rn,
    hsc.student_no,
    hsc.core,
    row_number() OVER(ORDER BY hsc.core DESC) ranks
    FROM hand_student_core hsc) hs ORDER BY CASE
    WHEN ranks <= 3 THEN
    -ranks
    ELSE
    null
    END,
    rn;

    这是一次过程考核的题目,考的很糟,继续学习吧。共勉。

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  • 原文地址:https://www.cnblogs.com/jerryyj/p/9621576.html
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