CheckIO 题目解法(3)

1.binary-count  找出一个数字的二进制中1的个数:

checkio = lambda a: bin(a).count('1')

2.absolute-sorting 用绝对值进行排序:

def checkio(num_list):
    num_list = list(num_list)
    num_list.sort(cmp = lambda a,b:cmp(abs(a), abs(b)))
    return num_list

3.number-radix 任意进制转换，异常时候返回-1:

def checkio(s_num, base):
    try:
        return int(s_num, base)
    except ValueError:
        return -1

4.three-words 一个string中是否有三个连续单词,单词中不能出现非字母的字符:

def checkio(words):
    words_list = words.split(' ')
    length = len(words_list)
    if length < 3:
        return False
    is_word = map(lambda s: s.isalpha(), words_list)
    for i in xrange(0, length-2):
        if all((is_word[i], is_word[i + 1], is_word[i + 2])):
            return True
    return False

5.end-of-other   一些单词中是否有一个单词是以其他单词结尾的:

def checkio(words):
    words = list(words)
    length = len(words)
    if length == 1:
        return False
    if length == 2:
        if words[0].endswith(words[1]) or words[1].endswith(words[0]):
            return True
        #print words[0]
        #return True
    for i in xrange(length):
        for j in xrange(i + 1, length):
            if words[i].endswith(words[j]) or words[j].endswith(words[i]):
                return True 
    return False

 6. hamming-distance2 计算两个数字的汉明距离:

def checkio(n,m):
   return bin(n^m).count('1')

 7. funny-adding checkio也有a+b问题:

def checkio(*arg):
    return sum(arg)