注:先学习sql server里的递归CTE。
假设有兴趣表Hobbys
Name | Hobby |
小张 | 篮球,足球,羽毛球 |
Name | Hobby |
小张 | 篮球 |
小张 | 足球 |
小张 | 羽毛球 |
采用【递归cte】
with tempHobbys as (select Name,Hobby,charindex(',',Hobby)-1 endindex,0 startindex from Hobbys union all select Name,Hobby,charindex(',',Hobby,endindex+2)-1 endindex,endindex+2 startindex from tempHobbys where endindex>-1), with tempHobbys 2 as (select Name,Hobby,(case when endindex<0 then len(Hobby) else Hobby end) endindex,startindex from tempHobbys) select Name,substring(Hobby,startindex,endindex-startindex+1) Hobby from tempHobbys2