iOS十六进制和字符串的相互转换

感谢分享，亲测可用

NSString *dictString = [dict JSONFragment];//组合成的。

用这个就行了。。。

dictString==={"content":"Sadgfdfg","phoneno":"","email":"1049055935@qq.com"}===

// 十六进制转换为普通字符串的。
+ (NSString *)stringFromHexString:(NSString *)hexString { //

char *myBuffer = (char *)malloc((int)[hexString length] / 2 + 1);
bzero(myBuffer, [hexString length] / 2 + 1);
for (int i = 0; i < [hexString length] - 1; i += 2) {
unsigned int anInt;
NSString * hexCharStr = [hexString substringWithRange:NSMakeRange(i, 2)];
NSScanner * scanner = [[[NSScanner alloc] initWithString:hexCharStr] autorelease];
[scanner scanHexInt:&anInt];
myBuffer[i / 2] = (char)anInt;
}
NSString *unicodeString = [NSString stringWithCString:myBuffer encoding:4];
NSLog(@"------字符串=======%@",unicodeString);
return unicodeString;


}

//普通字符串转换为十六进制的。

+ (NSString *)hexStringFromString:(NSString *)string{
NSData *myD = [string dataUsingEncoding:NSUTF8StringEncoding];
Byte *bytes = (Byte *)[myD bytes];
//下面是Byte 转换为16进制。
NSString *hexStr=@"";
for(int i=0;i<[myD length];i++)

{
NSString *newHexStr = [NSString stringWithFormat:@"%x",bytes[i]&0xff];///16进制数

if([newHexStr length]==1)

hexStr = [NSString stringWithFormat:@"%@0%@",hexStr,newHexStr];

else

hexStr = [NSString stringWithFormat:@"%@%@",hexStr,newHexStr];
}
return hexStr;
}