• PAT A1065 A+B and C (64bit) (20 分)


    AC代码

    #include <cstdio>
    
    int main() {
        #ifdef ONLINE_JUDGE
        #else
            freopen("1.txt", "r", stdin);
        #endif // ONLINE_JUDGE
        char str[2][10] = {"false", "true"};
        int n, tcase = 1;
        scanf("%d", &n);
        for(int i = 0; i < n; i++) {
    		int flag = 0;
            long long a, b, c;
            scanf("%lld%lld%lld", &a, &b, &c);
            long long d = a + b;
            //printf("%lld %lld %lld %lld
    ", a, b, c, d);
            /*if(c - b >= a) {
    			flag = 0;
    			printf("flag:%d
    ", flag);
    		} else {
    			flag = 1;
    			printf("flag:%d
    ", flag);
    		}*/
    		if(a > 0 && b > 0  && d < 0) flag = 1;
    		else if(a < 0 && b < 0 && d >= 0) flag = 0;
    		else if(d > c) flag = 1;
    		else flag = 0;
            printf("Case #%d: %s
    ", tcase++, str[flag]);
        }
        return 0;
    }
    
  • 相关阅读:
    leetcode-String to Integer (atoi)
    2014薪水
    Ubunt下的软件集
    ubuntu常用软件
    python模块安装
    ubuntu下玩三国杀
    递归函数
    匿名函数
    装饰器函数
    生成器
  • 原文地址:https://www.cnblogs.com/isChenJY/p/11213460.html
Copyright © 2020-2023  润新知