PreviousPage:获取向当前页传输控件的页
1，不采用强类型方式访问
Page1页面：
<%@ Page Language="C#" AutoEventWireup="true" CodeFile="Page1.aspx.cs" Inherits="Page1" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
<title>Untitled Page</title>
</head>
<body>
<form id="form1" runat="server">
<div>
<asp:TextBox ID="txtName" runat="server"></asp:TextBox>
<br />
<asp:Button ID="Button1" runat="server" Text="Button" PostBackUrl="~/Page2.aspx" /></div>
</form>
</body>
</html>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
<title>Untitled Page</title>
</head>
<body>
<form id="form1" runat="server">
<div>
<asp:TextBox ID="txtName" runat="server"></asp:TextBox>
<br />
<asp:Button ID="Button1" runat="server" Text="Button" PostBackUrl="~/Page2.aspx" /></div>
</form>
</body>
</html>
Page2代码：
using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
public partial class Page2 : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
if (PreviousPage != null)
{
TextBox txtName = (TextBox)PreviousPage.FindControl("txtName");
Response.Write("Hello " + txtName.Text);
}
}
}
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
public partial class Page2 : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
if (PreviousPage != null)
{
TextBox txtName = (TextBox)PreviousPage.FindControl("txtName");
Response.Write("Hello " + txtName.Text);
}
}
}
在接受Page1传过来的数据是，要先通过PreviousPage的FindControl找的控件在取值。
2，采用强类型方式访问
在Page1的代码中添加一个property
public string strName
{
get { return this.txtName.Text; }
}
{
get { return this.txtName.Text; }
}
然后在Page2的页面中添加指令
<%@ PreviousPageType VirtualPath="~/Page1.aspx" %>
这时，我们就可以在Page2的代码中使用PreviousPage的强类型属性了
using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
public partial class Page2 : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
if (PreviousPage != null)
{
//TextBox txtName = (TextBox)PreviousPage.FindControl("txtName");
//Response.Write("Hello " + txtName.Text);
Response.Write(PreviousPage.strName);
}
}
}
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
public partial class Page2 : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
if (PreviousPage != null)
{
//TextBox txtName = (TextBox)PreviousPage.FindControl("txtName");
//Response.Write("Hello " + txtName.Text);
Response.Write(PreviousPage.strName);
}
}
}
作者：冰碟
出处：http://www.cnblogs.com/icebutterfly/
版权：本文版权归作者和博客园共有
转载：欢迎转载，为了保存作者的创作热情，请按要求【转载】，谢谢
要求：未经作者同意，必须保留此段声明；必须在文章中给出原文连接；否则必究法律责任
出处：http://www.cnblogs.com/icebutterfly/
版权：本文版权归作者和博客园共有
转载：欢迎转载，为了保存作者的创作热情，请按要求【转载】，谢谢
要求：未经作者同意，必须保留此段声明；必须在文章中给出原文连接；否则必究法律责任