Given a non-negative integer num
, repeatedly add all its digits until the result has only one digit.
For example:
Given num = 38
, the process is like: 3 + 8 = 11
, 1 + 1 = 2
. Since 2
has only one digit, return it.
Follow up:
Could you do it without any loop/recursion in O(1) runtime?
1 public int addDigits(int num) 2 { 3 if (num/10==0) return num; 4 int sum = 0; 5 while(num!=0) 6 { 7 sum= sum+num%10; 8 num= num/10; 9 } 10 return addDigits(sum); 11 12 }