• 如何在不同编程语言中获取现在的Unix时间戳(Unix timestamp)


    Java time
    JavaScript Math.round(new Date().getTime()/1000)
    getTime()返回数值的单位是毫秒
    Microsoft .NET / C# epoch = (DateTime.Now.ToUniversalTime().Ticks - 621355968000000000) / 10000000
    MySQL SELECT unix_timestamp(now())
    Perl time
    PHP time()
    PostgreSQL SELECT extract(epoch FROM now())
    Python 先 import time 然后 time.time()
    Ruby 获取Unix时间戳:Time.now 或 Time.new
    显示Unix时间戳:Time.now.to_i
    SQL Server SELECT DATEDIFF(s, '1970-01-01 00:00:00', GETUTCDATE())
    Unix / Linux date +%s
    VBScript / ASP DateDiff("s", "01/01/1970 00:00:00", Now())
    其他操作系统
    (如果Perl被安装在系统中)
    命令行状态:perl -e "print time"
    如何在不同编程语言中实现Unix时间戳(Unix timestamp) → 普通时间?
    Java String date = new java.text.SimpleDateFormat("dd/MM/yyyy HH:mm:ss").format(new java.util.Date(Unix timestamp * 1000))
    JavaScript 先 var unixTimestamp = new Date(Unix timestamp * 1000) 然后commonTime = unixTimestamp.toLocaleString()
    Linux date -d @Unix timestamp
    MySQL from_unixtime(Unix timestamp)
    Perl 先 my $time = Unix timestamp 然后 my ($sec, $min, $hour, $day, $month, $year) = (localtime($time))[0,1,2,3,4,5,6]
    PHP date('r', Unix timestamp)
    PostgreSQL SELECT TIMESTAMP WITH TIME ZONE 'epoch' + Unix timestamp) * INTERVAL '1 second';
    Python 先 import time 然后 time.gmtime(Unix timestamp)
    Ruby Time.at(Unix timestamp)
    SQL Server DATEADD(s, Unix timestamp, '1970-01-01 00:00:00')
    VBScript / ASP DateAdd("s", Unix timestamp, "01/01/1970 00:00:00")
    其他操作系统
    (如果Perl被安装在系统中)
    命令行状态:perl -e "print scalar(localtime(Unix timestamp))"
    如何在不同编程语言中实现普通时间 → Unix时间戳(Unix timestamp)?
    Java long epoch = new java.text.SimpleDateFormat("dd/MM/yyyy HH:mm:ss").parse("01/01/1970 01:00:00");
    JavaScript var commonTime = new Date(Date.UTC(yearmonth - 1, dayhour,minutesecond))
    MySQL SELECT unix_timestamp(time)
    时间格式: YYYY-MM-DD HH:MM:SS 或 YYMMDD 或 YYYYMMDD
    Perl 先 use Time::Local 然后 my $time = timelocal($sec, $min, $hour, $day, $month, $year);
    PHP mktime(hourminutesecondmonthdayyear)
    PostgreSQL SELECT extract(epoch FROM date('YYYY-MM-DD HH:MM:SS'));
    Python 先 import time 然后 int(time.mktime(time.strptime('YYYY-MM-DD HH:MM:SS', '%Y-%m-%d %H:%M:%S')))
    Ruby Time.local(yearmonthdayhourminutesecond)
    SQL Server SELECT DATEDIFF(s, '1970-01-01 00:00:00', time)
    Unix / Linux date +%s -d"Jan 1, 1970 00:00:01"
    VBScript / ASP DateDiff("s", "01/01/1970 00:00:00", time)
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  • 原文地址:https://www.cnblogs.com/hwisecn/p/4899897.html
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