• 2014 网选 5007 Post Robot(暴力或者AC_自动机(有点小题大作了))


    //暴力,从每一行的开始处开始寻找要查询的字符
    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    
    char str[100005];
    
    int main(){
        while(gets(str)){
            for(int i=0; str[i]; ++i)
                if(str[i]=='A'){
                    if(strstr(str+i, "Apple") == str+i)
                        printf("MAI MAI MAI!
    ");
                }
                else if(str[i]=='i'){
                    if(strstr(str+i, "iPhone") == str+i || strstr(str+i, "iPod") == str+i || strstr(str+i, "iPad") == str+i)
                        printf("MAI MAI MAI!
    ");
                }
                else if(str[i]=='S')
                    if(strstr(str+i, "Sony") == str+i)
                        printf("SONY DAFA IS GOOD!
    ");
        }
        return 0;
    } 
     1 //将要匹配的字符串(也就是题目中查询文本中出现的5个单词)建立trie树,然后生成AC_自动机.....
     2 #include<iostream>
     3 #include<cstring>
     4 #include<queue>
     5 #include<cstdio>
     6 #include<algorithm>
     7 using namespace std;
     8 
     9 int trie[30][200];
    10 int vis[30], fail[6000];//vis标记的是单词的末尾字符所在的节点
    11 char str[][10] = {"Apple", "iPhone", "iPod", "iPad", "Sony"};
    12 int cnt;
    13 void buildT(){
    14     for(int i=0; i<5; ++i){
    15         int u=0;
    16         for(int j=0; str[i][j]; ++j){
    17             if(trie[u][str[i][j]] == 0)
    18                 trie[u][str[i][j]] = ++cnt;
    19             u=trie[u][str[i][j]];
    20         }
    21         vis[u]=1;
    22     }
    23 }
    24 
    25 void getFail(){
    26     queue<int>q;
    27     for(int i=0; i<200; ++i)
    28         if(trie[0][i]) q.push(trie[0][i]);
    29     while(!q.empty()){
    30         int u = q.front();
    31         q.pop();
    32         int v;
    33         for(int i=0; i<200; ++i)
    34             if(v = trie[u][i]){
    35                 fail[v] = trie[fail[u]][i];
    36                 q.push(v);
    37             }
    38             else
    39                 trie[u][i] = trie[fail[u]][i];
    40     }
    41 }
    42 
    43 void getText(char *ch){
    44     int u=0;
    45     for(int i=0; ch[i]; ++i){
    46         int v = trie[u][ch[i]];
    47         u=v;
    48         while(v){
    49             if(vis[v] && (ch[i]=='d' || ch[i]=='e'))
    50                 printf("MAI MAI MAI!
    ");
    51             else if(vis[v] && ch[i]=='y')
    52                 printf("SONY DAFA IS GOOD!
    "); 
    53             v = fail[v];
    54         }
    55     }
    56 }
    57 
    58 char text[10000];
    59 
    60 int main(){
    61     buildT();
    62     getFail();
    63     while(gets(text)){
    64         getText(text);
    65     }
    66     return 0;
    67 }
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  • 原文地址:https://www.cnblogs.com/hujunzheng/p/3973972.html
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