restlet 过滤器实现静态文件编码

restlet如何实现filter参考 : 

https://www.cnblogs.com/hi-gdl/p/11451648.html

下面是实现静态文件编码(解决乱码问题)的代码

    protected void afterHandle(Request request, Response response) {
        Reference ref=request.getResourceRef();
        String originalPath=ref.getPath();//原始路径
        String extension = PathUtil.getStaticSourcePathExtension(originalPath);
        if(extension.equalsIgnoreCase("js")
                || extension.equalsIgnoreCase("css")
                || extension.equalsIgnoreCase("html")
                || extension.equalsIgnoreCase("htm")
                ) {
            response.getEntity().setCharacterSet(CharacterSet.UTF_8);
        }

        super.afterHandle(request, response);
    }

工具类 PathUtil 的代码片段

    /**
     * <p>Title: getPathExtension</p>  
     * <p>Description: 获取静态文件路径的后缀
     *     <br>示例 : <pre>
     *     http://127.0.0.1:8080/aaa/bbb  ==>  ''
     *     http://127.0.0.1:8080/aaa/bbb?t=12  ==>  ''
     *     http://127.0.0.1:8080/aaa/bbb.js  ==>  'js'
     *     http://127.0.0.1:8080/aaa/bbb.js?t=123  ==>  'js'
     *     http://127.0.0.1:8080/aaa/bbb.js?t=123&a=1  ==>  'js'
     *     http://127.0.0.1:8080/aaa/bbb.css?t=123&a=1  ==>  'css'
     *     http://127.0.0.1:8080/aaa/bbb.css.bak?t=123&a=1  ==>  'bak'
     *     </pre>
     * </p>  
     * @param path
     * @return
     */
    public static String getStaticSourcePathExtension(String path) {
        if(StringUtils.isEmpty(path)) {
            return null ;
        }
        String str = null ;
        int url_param_split = path.indexOf('?');
        if(-1 != url_param_split) {
            str = path.substring(0,url_param_split);
        }else {
            str = new String(path);
        }
        int extension_split = str.lastIndexOf('.');
        if(-1 == extension_split) {
            return "";//没有后缀 , 显示空字符串
        }
        str = str.substring(extension_split+1);
        return str ;
    }
}