打开chrome 开发者工具
登录你访问的系统,复制你后台系统提供的url
在Console中输入如下代码 可发送http post/get请求
POST请求:
//方法一: var url = "/dict/test"; var params = {advertiserUid: 1232131, advertiserWeiboNickname: "18"}; var xhr = new XMLHttpRequest(); xhr.open("POST", url, true); xhr.setRequestHeader("Content-Type", "application/json"); xhr.onload = function (e) { if (xhr.readyState === 4) { if (xhr.status === 200) { console.log(xhr.responseText); } else { console.error(xhr.statusText); } } }; xhr.onerror = function (e) { console.error(xhr.statusText); }; xhr.send(JSON.stringify(params)); //方法二: var url = "/dict/test"; var params = "score=5&abc=6"; var xhr = new XMLHttpRequest(); xhr.open("POST", url, true); xhr.setRequestHeader("Content-type","application/x-www-form-urlencoded"); xhr.onload = function (e) { if (xhr.readyState === 4) { if (xhr.status === 200) { console.log(xhr.responseText); } else { console.error(xhr.statusText); } } }; xhr.onerror = function (e) { console.error(xhr.statusText); }; xhr.send(params);
GET请求:
1 var url = "/v1/query/listDicts?types=userType,userStatus"; 2 var xhr = new XMLHttpRequest(); 3 xhr.open("GET", url, true); 4 xhr.onload = function (e) { 5 if (xhr.readyState === 4) { 6 if (xhr.status === 200) { 7 console.log(xhr.responseText); 8 } else { 9 console.error(xhr.statusText); 10 } 11 } 12 }; 13 xhr.onerror = function (e) { 14 console.error(xhr.statusText); 15 }; 16 xhr.send(null);