Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4
and you are given the third node with value 3
, the linked list should become 1 -> 2 -> 4
after calling your function.
思路:
假如链表1 -> 2 -> 3 -> 4 删除2的时候,可以将2指向4,然后将2的值替换为3的值即可。
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: void deleteNode(ListNode* node) { int next = node->next->val; node->val = next; node->next = node->next->next; } };