• Codeforces Round #479 (Div. 3)


    Codeforces Round #479 (Div. 3)

    还是( m Div.3)比较娱乐身心...虽然我因为罚时名次比较低...

    A. Wrong Subtraction

    模拟。

    #include<bits/stdc++.h>
    using namespace std;
    
    #define int long long 
    
    void read(int &x) {
        x=0;int f=1;char ch=getchar();
        for(;!isdigit(ch);ch=getchar()) if(ch=='-') f=-f;
        for(;isdigit(ch);ch=getchar()) x=x*10+ch-'0';x*=f;
    }
     
    void print(int x) {
        if(x<0) putchar('-'),x=-x;
        if(!x) return ;print(x/10),putchar(x%10+48);
    }
    void write(int x) {if(!x) putchar('0');else print(x);putchar('
    ');}
    
    #define lf double
    #define ll long long 
    
    #define pii pair<int,int >
    #define vec vector<int >
    
    #define pb push_back
    #define mp make_pair
    #define fr first
    #define sc second
    
    #define FOR(i,l,r) for(int i=l,i##_r=r;i<=i##_r;i++) 
    
    const int maxn = 2e5+10;
    const int inf = 1e9;
    const lf eps = 1e-8;
    const int mod = 1e9+7;
    
    int n,a[maxn],k;
    
    signed main() {
        read(n),read(k);
        for(int i=1;i<=k;i++)
            if(n%10==0) n/=10;
            else n--;
        write(n);
        return 0;
    }
    

    B. Two-gram

    继续模拟...

    #include<bits/stdc++.h>
    using namespace std;
    
    #define int long long 
    
    void read(int &x) {
        x=0;int f=1;char ch=getchar();
        for(;!isdigit(ch);ch=getchar()) if(ch=='-') f=-f;
        for(;isdigit(ch);ch=getchar()) x=x*10+ch-'0';x*=f;
    }
     
    void print(int x) {
        if(x<0) putchar('-'),x=-x;
        if(!x) return ;print(x/10),putchar(x%10+48);
    }
    void write(int x) {if(!x) putchar('0');else print(x);putchar('
    ');}
    
    #define lf double
    #define ll long long 
    
    #define pii pair<int,int >
    #define vec vector<int >
    
    #define pb push_back
    #define mp make_pair
    #define fr first
    #define sc second
    
    #define FOR(i,l,r) for(int i=l,i##_r=r;i<=i##_r;i++) 
    
    const int maxn = 2e5+10;
    const int inf = 1e9;
    const lf eps = 1e-8;
    const int mod = 1e9+7;
    
    int n,a[maxn],k;
    
    char s[maxn];
    
    signed main() {
        read(n);scanf("%s",s+1);int mx=0,p=0;
        for(int i=1,t;i<n;i++) {
            a[t=s[i]*100+s[i+1]]++;
            if(a[t]>mx) mx=a[t],p=t;
        }
        putchar(p/100),putchar(p%100);
        return 0;
    }
    

    C. Less or Equal

    奇怪的判判判...( m WA)了好几次,总之( m sort)就行了。

    #include<bits/stdc++.h>
    using namespace std;
    
    #define int long long 
    
    void read(int &x) {
        x=0;int f=1;char ch=getchar();
        for(;!isdigit(ch);ch=getchar()) if(ch=='-') f=-f;
        for(;isdigit(ch);ch=getchar()) x=x*10+ch-'0';x*=f;
    }
     
    void print(int x) {
        if(x<0) putchar('-'),x=-x;
        if(!x) return ;print(x/10),putchar(x%10+48);
    }
    void write(int x) {if(!x) putchar('0');else print(x);putchar('
    ');}
    
    #define lf double
    #define ll long long 
    
    #define pii pair<int,int >
    #define vec vector<int >
    
    #define pb push_back
    #define mp make_pair
    #define fr first
    #define sc second
    
    #define FOR(i,l,r) for(int i=l,i##_r=r;i<=i##_r;i++) 
    
    const int maxn = 2e5+10;
    const int inf = 1e9;
    const lf eps = 1e-8;
    const int mod = 1e9+7;
    
    int n,a[maxn],k;
    
    signed main() {
        read(n),read(k);FOR(i,1,n) read(a[i]);
        sort(a+1,a+n+1);
        if(k==0) puts(a[1]==1?"-1":"1");
        else if(a[k+1]==a[k]) puts("-1");
        else write(a[k]);
        return 0;
    }
    

    D. Divide by three, multiply by two

    因为保证有解,(O(n^2))枚举之后建图爆搜就行了。

    #include<bits/stdc++.h>
    using namespace std;
    
    #define int long long 
    
    void read(int &x) {
        x=0;int f=1;char ch=getchar();
        for(;!isdigit(ch);ch=getchar()) if(ch=='-') f=-f;
        for(;isdigit(ch);ch=getchar()) x=x*10+ch-'0';x*=f;
    }
     
    void print(int x) {
        if(x<0) putchar('-'),x=-x;
        if(!x) return ;print(x/10),putchar(x%10+48);
    }
    void write(int x) {if(!x) putchar('0');else print(x);putchar('
    ');}
    
    #define lf double
    #define ll long long 
    
    #define pii pair<int,int >
    #define vec vector<int >
    
    #define pb push_back
    #define mp make_pair
    #define fr first
    #define sc second
    
    #define FOR(i,l,r) for(int i=l,i##_r=r;i<=i##_r;i++) 
    
    const int maxn = 1e5+10;
    const int inf = 1e9;
    const lf eps = 1e-8;
    const int mod = 1e9+7;
    
    int n,a[maxn],head[maxn],tot,d[maxn],sta[maxn],top,vis[maxn],out[maxn];
    
    struct edge{int to,nxt;}e[maxn<<1];
    
    void ins(int u,int v) {e[++tot]=(edge){v,head[u]},head[u]=tot,d[v]++,out[u]++;}
    
    void dfs(int x) {
        sta[++top]=x;
        if(!out[x]) {
            for(int i=1;i<=top;i++) printf("%I64d ",a[sta[i]]);puts("");
            exit(0);
        }
        for(int i=head[x];i;i=e[i].nxt) dfs(e[i].to);
        top--;
    }
    
    signed main() {
        read(n);FOR(i,1,n) read(a[i]);
        FOR(i,1,n) FOR(j,1,n) if(i!=j) {
            if(a[i]*2==a[j]) ins(i,j);
            else if(a[j]==a[i]/3&&a[i]%3==0) ins(i,j);
        }
        FOR(i,1,n) if(!d[i]) dfs(i);
        return 0;
    }
    

    E. Cyclic Components

    爆搜题,环的性质满足每个点度数为(2),复杂度(O(n+m))

    #include<bits/stdc++.h>
    using namespace std;
    
    #define int long long 
    
    void read(int &x) {
        x=0;int f=1;char ch=getchar();
        for(;!isdigit(ch);ch=getchar()) if(ch=='-') f=-f;
        for(;isdigit(ch);ch=getchar()) x=x*10+ch-'0';x*=f;
    }
     
    void print(int x) {
        if(x<0) putchar('-'),x=-x;
        if(!x) return ;print(x/10),putchar(x%10+48);
    }
    void write(int x) {if(!x) putchar('0');else print(x);putchar('
    ');}
    
    #define lf double
    #define ll long long 
    
    #define pii pair<int,int >
    #define vec vector<int >
    
    #define pb push_back
    #define mp make_pair
    #define fr first
    #define sc second
    
    #define FOR(i,l,r) for(int i=l,i##_r=r;i<=i##_r;i++) 
    
    const int maxn = 5e5+10;
    const int inf = 1e9;
    const lf eps = 1e-8;
    const int mod = 1e9+7;
    
    int n,a[maxn],head[maxn],tot,cnt,vis[maxn],sz,m,ans,d[maxn],bo=1;
    struct edge{int to,nxt;}e[maxn];
    
    void ins(int u,int v) {d[u]++;e[++tot]=(edge){v,head[u]},head[u]=tot;}
    
    void dfs(int x) {
        vis[x]=1;if(d[x]!=2) bo=0;
        for(int i=head[x];i;i=e[i].nxt) 
            if(!vis[e[i].to]) dfs(e[i].to);
    }
    
    signed main() {
        read(n),read(m);
        for(int i=1,x,y;i<=m;i++) read(x),read(y),ins(x,y),ins(y,x);
        for(int i=1;i<=n;i++) if(!vis[i]) dfs(i),ans+=bo,bo=1;
        write(ans);
        return 0;
    }
    

    F. Consecutive Subsequence

    ( m dp),考虑一个暴力的玩意,设(f[i][j])表示当前(i)位结尾为(j)的最大长度。

    第一维可以滚动,注意到每个数只能影响到一个状态,所以总状态很少,可以开( m map)存第二维。

    方案直接记录最大的那个以什么结尾,倒着扫一遍就好了。

    #include<bits/stdc++.h>
    using namespace std;
    
    #define int long long 
    
    void read(int &x) {
        x=0;int f=1;char ch=getchar();
        for(;!isdigit(ch);ch=getchar()) if(ch=='-') f=-f;
        for(;isdigit(ch);ch=getchar()) x=x*10+ch-'0';x*=f;
    }
     
    void print(int x) {
        if(x<0) putchar('-'),x=-x;
        if(!x) return ;print(x/10),putchar(x%10+48);
    }
    void write(int x) {if(!x) putchar('0');else print(x);putchar('
    ');}
    
    #define lf double
    #define ll long long 
    
    #define pii pair<int,int >
    #define vec vector<int >
    
    #define pb push_back
    #define mp make_pair
    #define fr first
    #define sc second
    
    #define FOR(i,l,r) for(int i=l,i##_r=r;i<=i##_r;i++) 
    
    const int maxn = 5e5+10;
    const int inf = 1e9;
    const lf eps = 1e-8;
    const int mod = 1e9+7;
    
    int n,a[maxn],ans,p,sta[maxn],top;
    
    map<int,int > f;
    
    signed main() {
        read(n);FOR(i,1,n) read(a[i]);
        for(int i=1,x;i<=n;i++) {
            x=f[a[i]]=max(f[a[i]-1]+1,f[a[i]]);
            if(x>ans) ans=x,p=a[i];
        }
        write(ans);
        for(int i=n;i;i--)
            if(a[i]==p) sta[++top]=i,p--;
        while(top) printf("%I64d ",sta[top--]);puts("");
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/hbyer/p/11028282.html
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