• Implement Queue using Stacks


    Description:

    Implement the following operations of a queue using stacks.

    • push(x) -- Push element x to the back of queue.
    • pop() -- Removes the element from in front of queue.
    • peek() -- Get the front element.
    • empty() -- Return whether the queue is empty.

    Notes:

      • You must use only standard operations of a stack -- which means only push to toppeek/pop from topsize, and is empty operations are valid.
      • Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
      • You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).

    Code:

    class Queue {
    public:
        // Push element x to the back of queue.
        stack<int>in;
        stack<int>out;
        void push(int x) {
            in.push(x);
        }
    
        // Removes the element from in front of queue.
        void pop(void) {
            if (out.empty())
            {
                while (!in.empty())
                {
                    out.push(in.top());
                    in.pop();
                }
            }
            if (!out.empty())
                out.pop();
        }
    
        // Get the front element.
        int peek(void) {
            if (out.empty())
            {
                while (!in.empty())
                {
                    out.push(in.top());
                    in.pop();
                }
            }
            if (!out.empty())
                return out.top();
        }
    
        // Return whether the queue is empty.
        bool empty(void) {
            return in.empty() && out.empty();
        }
    };
  • 相关阅读:
    JS eval()小结
    纯JS的ajax实例
    js特效代码-鼠标样式
    JS typeof与instanceof的区别
    linux下网卡绑定
    KVM+VNC 虚拟机远程管理
    smokeping安装
    Python:字符串中引用外部变量的3种方法
    Python:模块学习——os模块
    Python:模块学习——sys模块
  • 原文地址:https://www.cnblogs.com/happygirl-zjj/p/4752096.html
Copyright © 2020-2023  润新知