• [******] 树问题:普通二叉树的创建与遍历


    1. 二叉树的创建

    String pre_str = "1,2,4,8,-1,-1,9,-1,-1,5,-1,-1,3,6,-1,10,-1,-1,7,-1,-1";//先序输入
    String post_str = "-1,-1,8,-1,-1,9,4,-1,-1,5,2,-1,-1,-1,10,6,-1,-1,7,3,1";//后序输入
    String level_str = "1,2,3,4,5,6,7,8,9,-1,-1,-1,10,-1,-1";//层次输入
    int[] in = {8,4,9,2,5,1,6,10,3,7}; //中序
    int[] pre = {1,2,4,8,9,5,3,6,10,7}; //先序
    int[] post = {8,9,4,5,2,10,6,7,3,1}; //后序
    String input = "1(2(4(8,9),5),3(6(,10),7))";//括号表达式输入
        static class TreeNode{
            int value;
            TreeNode left;
            TreeNode right;
            public TreeNode(int value){
                this.value = value;
            }
        }

    1.1 前序遍历创建二叉树

    核心思路:根左右,从左往右读

      /**先序方法1*/
        public static TreeNode pre_buildBTree1(InputChar ic, int flag) {
            int x = ic.pregetChar();
            if (x == flag)
                return null;
            TreeNode t = new TreeNode(x);
            t.left = pre_buildBTree1(ic,flag);
            t.right = pre_buildBTree1(ic,flag);
            return t;
        }
        /**先序方法2*/
        public static int position = -1;
        public static TreeNode pre_buildBTree2(int[] array, int flag) {
            int x = array[++position];
            TreeNode node = null;
            if(position < array.length && x != flag){
                node = new TreeNode(x);
                node.left = pre_buildBTree2(array,flag);
                node.right = pre_buildBTree2(array,flag);
            }
            return node;
        }
    
      /***用于获取值 */
        static class InputChar {
            private int[] array;
            private int pos = 0;
    
            public InputChar(int[] array,int pos) {
                this.array = array;
                this.pos = pos;
            }
            public int pregetChar() {
                int i = pos;
                pos++;
                return array[i];
            }
            public int postgetChar() {
                int i = pos;
                pos--;
                return array[i];
            }
        }
    
        public static void main(String[] args) {
            /***********************先序创建二叉树***********************/
            String pre_str = "1,2,4,8,-1,-1,9,-1,-1,5,-1,-1,3,6,-1,10,-1,-1,7,-1,-1";//先序
            String[] array = pre_str.split(",");
            int [] intarray = new int[array.length];
            for (int i = 0; i < intarray.length; i++) {
                intarray[i]=Integer.valueOf(array[i]);
            }
            //第一种先序遍历创建二叉树方法
            InputChar inint = new InputChar(intarray,0);
            TreeNode root1 = pre_buildBTree1(inint,-1);
            //第二种先序遍历创建二叉树方法
            position = -1;
            TreeNode root2 = pre_buildBTree2(intarray,-1);
            root1 = root2;
       }    

    1.2 后序遍历创建二叉树

    核心思路:左右根,从右往左读  

      /**后序方法1*/
        public static TreeNode post_buildBTree1(InputChar ic, int flag) {
            int x = ic.postgetChar();
            if (x == flag)
                return null;
            TreeNode t = new TreeNode(x);//根
            t.right = post_buildBTree1(ic,flag);//右
            t.left = post_buildBTree1(ic,flag);//左
            return t;
        }
        /**后序方法2*/
        public static TreeNode post_buildBTree2(int[] array, int flag) {
            int x = array[--position];
            TreeNode node = null;
            if(position >= 0 && x != flag){
                node = new TreeNode(x);
                node.right = post_buildBTree2(array,flag);
                node.left = post_buildBTree2(array,flag);
            }
            return node;
        }
      /***用于获取值 */
        static class InputChar {
            private int[] array;
            private int pos = 0;
    
            public InputChar(int[] array,int pos) {
                this.array = array;
                this.pos = pos;
            }
            public int pregetChar() {
                int i = pos;
                pos++;
                return array[i];
            }
            public int postgetChar() {
                int i = pos;
                pos--;
                return array[i];
            }
        }
        public static void main(String[] args) {
         /***********************后序创建二叉树***********************/
            String post_str = "-1,-1,8,-1,-1,9,4,-1,-1,5,2,-1,-1,-1,10,6,-1,-1,7,3,1";//后序
            String[] array2 = post_str.split(",");
            int [] intarray2 = new int[array.length];
            for (int i = 0; i < intarray.length; i++) {
                intarray2[i]=Integer.valueOf(array2[i]);
            }
            //第一种先序遍历创建二叉树方法
            InputChar inint2 = new InputChar(intarray2,intarray2.length-1);
            TreeNode root3 = post_buildBTree1(inint2,-1);
            root1 = root3;
            //第二种先序遍历创建二叉树方法
            position = intarray2.length;
            TreeNode root4 = post_buildBTree2(intarray2,-1);
            root1 = root4;    
        }

    1.3 层次遍历创建二叉树

    核心思路:利用二叉树的性质,左孩子=2*i,右孩子=2*i+1

      /**层次遍历创建二叉树*/
        public static TreeNode level_buildBTree(int[]array,int flag){
            int len = array.length;
            //将数组转成list
            LinkedList<TreeNode> list = new LinkedList<>();
            for (int i = 0; i < len; i++) {
                list.add(new TreeNode(array[i]));
            }
            //开始构建树
            for (int i = 0; i < len/2; i++) {
                list.get(i).left = list.get(2*i+1).value!=flag?list.get(2*i+1):null;
                //记得处理最后一个父节点(len/2-1),因为有可能没有右孩子。
                if(i<len/2-1 ||(i==len/2-1&& len%2!=0)){
                    list.get(i).right = list.get(2*i+2).value!=flag?list.get(2*i+2):null;
                }
            }
            return list.get(0);
        }
        public static void main(String[] args) {
        /***********************层次创建二叉树***********************/
            String level_str = "1,2,3,4,5,6,7,8,9,-1,-1,-1,10,-1,-1";//层次
            String[] array1 = level_str.split(",");
            int len = array1.length;
            int[] intlevelarray = new int[len];
            for (int i = 0; i < len; i++) {
                intlevelarray[i] = Integer.valueOf(array1[i]);
            }
            TreeNode  root5 = level_buildBTree(intlevelarray,-1);
            root1 = root5;
        }

    1.4 前序和中序创建二叉树

        /***从中序与先序遍历序列构造二叉树**/
        public static TreeNode inpre_buildTree(int[] preOrder, int[] inorder) {
            TreeNode root = inpre_buildTreehelper(preOrder, 0, preOrder.length - 1, inorder, 0, inorder.length - 1);
            return root;
        }
        private static TreeNode inpre_buildTreehelper(int[] preOrder, int preStart, int preEnd, int[] inorder, int inStart, int inEnd) {
            if (preStart > preEnd || inStart > inEnd) {
                return null;
            }
            int x = preOrder[preStart];
            TreeNode root = new TreeNode(x);
            for (int i = inStart; i <= inEnd; i++)
                if (inorder[i] == x) {
                    root.left = inpre_buildTreehelper(preOrder, preStart + 1, preStart + i - inStart, inorder, inStart, i - 1);
                    root.right = inpre_buildTreehelper(preOrder, i - inStart + preStart + 1, preEnd, inorder, i + 1, inEnd);
                    break;
                }
            return root;
        }
        public static void main(String[] args) {
        /***********************从中序与先序遍历序列构造二叉树***********************/
            int[] in = {8,4,9,2,5,1,6,10,3,7};
            int[] pre = {1,2,4,8,9,5,3,6,10,7};
            root1 = inpre_buildTree(pre, in);
        }

    1.5 后续和中序创建二叉树

    /***从中序与后序遍历序列构造二叉树**/
    public static TreeNode inpost_buildTree(int[] inorder, int[] postorder) {
        return inpost_buildTreehelper(postorder, 0, postorder.length - 1, inorder, 0, inorder.length - 1);
    }
        
    private static TreeNode inpost_buildTreehelper(int[] postorder,int postStart, int postEnd, int[] inorder,  int inStart, int inEnd){
        if (postStart > postEnd || inStart > inEnd) {
           return null;
        }
        int x = postorder[postEnd];
        TreeNode root = new TreeNode(x);
        for (int i = inStart; i <= inEnd; i++)
            if (inorder[i] == x) {
                root.left = inpost_buildTreehelper(postorder, postStart, postEnd-(inEnd - i)-1, inorder, inStart, i - 1);
                root.right = inpost_buildTreehelper(postorder, postEnd-(inEnd - i), postEnd-1, inorder, i + 1, inEnd);
                break;
            }
        return root;
    }
    public static void main(String[] args) { int[] in = {8,4,9,2,5,1,6,10,3,7}; int[] post = {8,9,4,5,2,10,6,7,3,1}; root1 = inpost_buildTree(in, post); }

    1.6 括号表达式创建二叉树

    //括号表达式构建二叉树
    static TreeNode kuohao__buildTree(String input) {
        char[] str = input.toCharArray();
        TreeNode root = null;
        TreeNode p = null;
        Stack<TreeNode> s = new Stack<TreeNode>();
        int i = 0;
        int k = 0;
        char ch = str[i];
        while(i<str.length){
            switch(ch){
                case '(':{
                    s.push(p);//括号左边的是父亲,入栈
                    k = 1;//括号右面的是左孩子
                    break;
                }
                case ',':{
                    k = 2;//逗号右边的是有孩子
                    break;
                }
                case ')':{
                    s.pop();//表示该节点的左右孩子已经确定,出栈
                    break;
                }
                default:{
                    int count = 0;
                    boolean flag = false;
                    while(i<str.length && (str[i] + "").matches("[0-9]")){
                        count = count * 10 + (str[i]-'0');
                        i++;
                        flag = true;
                    }
                    if (flag = true) i--;//为了判断数字,多加了一次,所以减去
                    p = new TreeNode(count);//保存多位数字
                    if(root==null){
                        root = p;//保存根节点
                    }else{
                        if(k==1){
                            s.peek().left = p;
                        }else if(k==2){
                            s.peek().right = p;
                        }
                    }
                    break;
                }
            }
            i++;
            if(i<str.length){
                ch = str[i];
            }
        }
        return root;
    }
    
    public static void main(String[] args) {
        /***********************括号表达式构造二叉树***********************/
        String input = "1(2(4(8,9),5),3(6(,10),7))";
        TreeNode root6 = kuohao__buildTree(input);
    }

    2. 二叉树的遍历

    2.1 前序遍历(根左右)

    /***递归先序遍历*/
        public static void preOrder(TreeNode root,List<TreeNode> preorder){
            if(root!=null){
                preorder.add(root);
                preOrder(root.left,preorder);
                preOrder(root.right,preorder);
            }
        }
    
    /***非递归先序遍历*/
        public static List<TreeNode> preOrderT(TreeNode root){
            List<TreeNode> list =  new LinkedList<TreeNode>();
            Stack<TreeNode> stack = new Stack<TreeNode>();
            if(root!=null){
                stack.push(root);
                while(!stack.empty()){
                    TreeNode cur = stack.pop();
                    list.add(cur);
                    if(cur.right!=null) stack.push(cur.right);
                    if(cur.left!=null) stack.push(cur.left);
                }
            }
            return list;
        }
        

    public static void main(String[] args) {      System.out.println("==========递归先序遍历========="); List<TreeNode> preorder = new LinkedList<TreeNode>(); preOrder(root1,preorder);//递归先序遍历 printNonLevel(preorder);//打印      System.out.println("==========非递归先序遍历========="); List<TreeNode> preorderT = preOrderT(root1);//非递归先序遍历 printNonLevel(preorderT);//打印 } /***************************打印*************************/ /** * 打印一维链表(先序,中序,后序) * @param List<TreeNode> treeNode */ public static void printNonLevel(List<TreeNode> treeNode){ for (int i = 0; i < treeNode.size(); i++) { System.out.print(treeNode.get(i).value+" "); } System.out.println(); }

    2.2 后序遍历(左右根)

    addFirst

    /***递归后序遍历*/
        public static void postOrder(TreeNode root,List<TreeNode> postorder){
            if(root!=null){
                postOrder(root.left,postorder);
                postOrder(root.right,postorder);
                postorder.add(root);
            }
        }
    /***非递归后序遍历*/
        public static List<TreeNode> postOrderT(TreeNode root){
            LinkedList<TreeNode> list =  new LinkedList<TreeNode>();
            Stack<TreeNode> stack = new Stack<TreeNode>();
            if(root!=null){
                stack.push(root);
                while(!stack.empty()){
                    TreeNode cur = stack.pop();
                    list.addFirst(cur);
                    if(cur.left!=null) stack.push(cur.left);
                    if(cur.right!=null) stack.push(cur.right);
                }
            }
            return list;
        }
    public static void main(String[] args) {
         System.out.println("==========递归后序遍历=========");
            List<TreeNode> postorder = new LinkedList<TreeNode>();
            postOrder(root1,postorder);//递归后序遍历
            printNonLevel(postorder);//打印
           System.out.println("==========非递归后序遍历=========");
            List<TreeNode> postorderT = postOrderT(root1);//递归后序遍历
            printNonLevel(postorderT);//打印  
    }
    /***************************打印*************************/
        /**
         * 打印一维链表(先序,中序,后序)
         * @param List<TreeNode>  treeNode
         */
        public static void printNonLevel(List<TreeNode> treeNode){
            for (int i = 0; i < treeNode.size(); i++) {
                System.out.print(treeNode.get(i).value+" ");
            }
            System.out.println();
        }

    2.3 中序遍历(左根右)

        /***递归中序遍历*/
        public static void inOrder(TreeNode root, List<TreeNode> inorder){
            if(root!=null){
                inOrder(root.left,inorder);
                inorder.add(root);
                inOrder(root.right,inorder);
            }
        }
    
        /***非递归中序遍历*/
        public static List<TreeNode> inOrderT(TreeNode root){
            List<TreeNode> list =  new LinkedList<TreeNode>();
            Stack<TreeNode> stack = new Stack<TreeNode>();
            TreeNode cur = root;
            while(cur!=null || !stack.empty()){
                while(cur!=null){
                    stack.push(cur);
                    cur = cur.left;
                }
                cur = stack.pop();
                list.add(cur);
                cur = cur.right;
            }
            return list;
        }
    public static void main(String[] args) {
          System.out.println("==========递归中遍历=========");
            List<TreeNode> inorder = new LinkedList<TreeNode>();
            inOrder(root1,inorder);//递归中序遍历
            printNonLevel(inorder);//打印
            System.out.println("==========非递归中序遍历=========");
            List<TreeNode> inorderT = inOrderT(root1);//非递归中序遍历
            printNonLevel(inorderT);//打印
     
    }
    /***************************打印*************************/
        /**
         * 打印一维链表(先序,中序,后序)
         * @param List<TreeNode>  treeNode
         */
        public static void printNonLevel(List<TreeNode> treeNode){
            for (int i = 0; i < treeNode.size(); i++) {
                System.out.print(treeNode.get(i).value+" ");
            }
            System.out.println();
        }

    2.4 广度优先遍历(层次遍历)

    /***广度优先遍历或者层次遍历*/
        public static List<List<TreeNode>> levelOrder(TreeNode root) {
            List<List<TreeNode>> res = new LinkedList<>();
            if (root == null) {
                return res;
            }
            levelOrderHelper(res, root, 0);
            return res;
        }
    
        /**二叉树的深度*/
        private static void levelOrderHelper(List<List<TreeNode>> res, TreeNode root, int depth) {
            if (root == null) {
                return;
            }
            if (res.size() <= depth) {
                res.add(new LinkedList<>());// 当前层的第一个节点,需要 new 一个 list 来存当前层.
            }
            res.get(depth).add(root);// depth 层,把当前节点加入
            // 递归的遍历下一层.
            levelOrderHelper(res, root.left, depth + 1);
            levelOrderHelper(res, root.right, depth + 1);
        }
    /**非递归 广度优先遍历或者层次遍历,用队列实现层次遍历*/ public static List<List<TreeNode>> levelOrderT(TreeNode root) { if(root == null) return new ArrayList<>(); List<List<TreeNode>> list = new ArrayList<>();
         if(root == null) return list; Queue
    <TreeNode> queue = new LinkedList<TreeNode>(); queue.offer(root); while(!queue.isEmpty()){ int count = queue.size(); List<TreeNode> levellist = new ArrayList<TreeNode>(); while(count > 0){ TreeNode node = queue.poll(); levellist.add(node); if(node.left != null) queue.offer(node.left); if(node.right != null) queue.offer(node.right); count--; } list.add(levellist); } return list; }
    public static void main(String[] args) { System.out.println("==========递归广度优先遍历 OR 层次遍历========="); List<List<TreeNode>> levelOrder = levelOrder(root1); printLevel(levelOrder); System.out.println("==========非递归层次遍历========="); List<List<TreeNode>> levelOrderT = levelOrderT(root1); printLevel(levelOrderT); }
    /** * 打印二维链表(层次) * @param List<List<TreeNode>> treeNode */ public static void printLevel(List<List<TreeNode>> levelOrder){ for (int i = 0; i < levelOrder.size(); i++) { for (int j = 0; j < levelOrder.get(i).size(); j++) { System.out.print(levelOrder.get(i).get(j).value +" "); } System.out.println(); } }

    2.4 深度优先遍历

     /*** 深度优先遍历*/
        public static void dfs(TreeNode node, List<List<TreeNode>> dfsResult, List<TreeNode> list) {
            if (node == null)
                return;
            if (node.left == null && node.right == null) {
                list.add(node);
                dfsResult.add(new ArrayList<>(list));//不能直接将list存入,需要新建一个list来实现,防止后序操作影响
                list.remove(list.size() - 1);//将其最后一个存的节点删掉回溯
            }
            list.add(node);
            dfs(node.left, dfsResult, list);
            dfs(node.right, dfsResult, list);
            list.remove(list.size() - 1);
        } 
    
    public static void main(String[] args) {
            System.out.println("==========非递归层次遍历=========");
            List<List<TreeNode>> levelOrderT = levelOrderT(root1);
            printLevel(levelOrderT);
        }
    
        /**
         * 打印二维链表(层次)
         * @param List<List<TreeNode>> treeNode
         */
        public static void printLevel(List<List<TreeNode>> levelOrder){
            for (int i = 0; i < levelOrder.size(); i++) {
                for (int j = 0; j < levelOrder.get(i).size(); j++) {
                    System.out.print(levelOrder.get(i).get(j).value +" ");
                }
                System.out.println();
            }
        }
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  • 原文地址:https://www.cnblogs.com/haimishasha/p/11441233.html
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