674. Longest Continuous Increasing Subsequence

问题：

求给定数组中，最长连续递增子数组

Example 1:
Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4. 

Example 2:
Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1. 

Note: Length of the array will not exceed 10,000.

　　

解法：

从第二项开始轮询数组，

当该项大于前一项，则当前记录子数组长度curres++

反之，curres=1当前子数组长度回归重新记录 1，并同时去curres和历来res的最大值 res=max(res, curres)

参考代码：

class Solution {
public:
    int findLengthOfLCIS(vector<int>& nums) {
        int i, res=1, curres=1;
        if(nums.size()<1) return 0;
        for(i=1; i<nums.size(); i++){
            if(nums[i]>nums[i-1]){
                curres++;
            }else{
                curres=1;
            }
            res=max(res,curres);
        }
        return res;
    }
};