Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋
times.
You may assume that the array is non-empty and the majority element always exist in the array.
Example 1:
Input: [3,2,3] Output: 3
Example 2:
Input: [2,2,1,1,1,2,2] Output: 2
Approach #1: HashMap. [C++]
class Solution { public: int majorityElement(vector<int>& nums) { map<int, int> mp; int n = nums.size(); int ans = 0; for (int num: nums) mp[num]++; map<int, int>::iterator it; it = mp.begin(); while (it != mp.end()) { if (it->second > n/2) ans = it->first; it++; } return ans; } };