228. Summary Ranges java solutions

Given a sorted integer array without duplicates, return the summary of its ranges.

For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"].

Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.

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public class Solution {
    public List<String> summaryRanges(int[] nums) {
        List<String> ans = new ArrayList<String>();
        if(nums == null || nums.length == 0) return ans;
        for(int i = 0; i < nums.length; i++){
            int n = nums[i];
            while(i+1 < nums.length && nums[i+1]-nums[i] == 1)i++;
            if(n != nums[i]){
                ans.add(n + "->" + nums[i]);
            }
            else ans.add(""+n);
        }
        return ans;
    }
}

主要是要注意下边界。