Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1and nums2 are m and n respectively.
1 public class Solution { 2 public void merge(int[] nums1, int m, int[] nums2, int n) { 3 if(n == 0) return; 4 int k = m + n - 1; 5 int i = m - 1; 6 int j = n - 1; 7 while(i >= 0 && j >= 0){ 8 if(nums1[i] > nums2[j]){ 9 nums1[k--] = nums1[i--]; 10 }else{ 11 nums1[k--] = nums2[j--]; 12 } 13 } 14 if(i < 0){//nums2 元素还有没处理完的 15 while(j >= 0)nums1[k--] = nums2[j--]; 16 } 17 } 18 }