题目描述:
A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same element.
Now given an M x N
matrix, return True
if and only if the matrix is Toeplitz.
Example 1:
Input: matrix = [ [1,2,3,4], [5,1,2,3], [9,5,1,2] ] Output: True Explanation: In the above grid, the diagonals are: "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]". In each diagonal all elements are the same, so the answer is True.
Example 2:
Input: matrix = [ [1,2], [2,2] ] Output: False Explanation: The diagonal "[1, 2]" has different elements.
Note:
matrix
will be a 2D array of integers.matrix
will have a number of rows and columns in range[1, 20]
.matrix[i][j]
will be integers in range[0, 99]
.
Follow up:
- What if the matrix is stored on disk, and the memory is limited such that you can only load at most one row of the matrix into the memory at once?
- What if the matrix is so large that you can only load up a partial row into the memory at once?
解题思路:
每次只读进一行时,读进的当前这一行与上一行进行比较。
代码:
1 class Solution { 2 public: 3 bool isToeplitzMatrix(vector<vector<int>>& matrix) { 4 bool sig = true; 5 vector<int> last = matrix[0]; 6 for (int i = 1; i < matrix.size(); ++i) { 7 for (int j = 1; j < matrix[i].size(); ++j) { 8 if (matrix[i][j] != last[j-1]) { 9 sig = false; 10 break; 11 } 12 } 13 if (sig) { 14 last = matrix[i]; 15 } else { 16 break; 17 } 18 } 19 return sig; 20 } 21 };