• 【CF1174E】Ehab and the Expected GCD Problem


    #include<bits/stdc++.h>
    using namespace std;
    typedef long long ll;
    const ll mod = 1e9+7;
    const int N = 1e6+5;
    int n;
    ll siz[N];
    ll d[2][25][25],pow2[25],pow3[25];
    void ycl(){
        int o=0;
        pow2[0] = pow3[0] = 1;
        for(int i=1;i<=n;i++){
            siz[i] = n/i;
        }
        for(int i=1;i<=20;i++){
            pow2[i] = pow2[i-1] * 2 % mod;
        }
        for(int i=1;i<=13;i++){
            pow3[i] = pow3[i-1] * 3 % mod;
    
        }
    }
    bool flag = 0;
    int main() {
        cin>>n;
        if(n <= 2) {
            cout<<1<<endl;
            return 0;
        }
        ycl();
        int nn = 0;
        while((1<<(nn+1))<=n) nn++;
        d[1][nn][0] = 1;
        if(pow2[nn-1]*3<=n) d[1][nn-1][1] = 1;
        int o = 1;
        ll ans = 0;
        for(int len=2;len<=n;len++){
            bool flag = 0;
            o = o^1;
            memset(d[o],0,sizeof(d[o]));
            for(int i=0;pow2[i]<=n;i++){
                for(int j=0;j<=1&&pow2[i]*pow3[j]<=n;j++) {
                    int now = pow2[i]*pow3[j];
                    d[o][i][j] += d[o^1][i][j]*(siz[now]-(len-1))%mod;
                    d[o][i][j] %= mod;
                    if(i>=1){
                        d[o][i-1][j] += d[o^1][i][j]*(siz[pow2[i-1]*pow3[j]]-siz[now])%mod;
                    }
                    if(j>=1){
                        d[o][i][j-1] += d[o^1][i][j]*(siz[pow2[i]*pow3[j-1]]-siz[now])%mod;
                    }
                }
            }
        }
        cout<<d[o][0][0]<<endl;
    }
    
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  • 原文地址:https://www.cnblogs.com/greenty1208/p/10975878.html
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