题意:有n个物品,希望尽可能均分
尽可能均分,就是找尽可能接近sum/2的方案
考虑生成函数 (G(x)=(1+x^{v[i]}+x^{2v[i]}+...+x^{a[i]v[i]})(...)
#include<bits/stdc++.h>
using namespace std;
int rd(){
int ret=0, f=1;char c;
while(c=getchar(),!isdigit(c))f=c=='-'?-1:1;
while(isdigit(c))ret=ret*10+c-'0',c=getchar();
return ret*f;
}
const int MAXN = 500005;
int n;
int val[MAXN],num[MAXN],sum,all;
int f[MAXN][2];
void solve(){
sum=0;
all=0;
for(int i=1;i<=n;i++){
val[i]=rd();num[i]=rd();
sum+=val[i]*num[i];
}
all=sum;
memset(f,0,sizeof(f));
f[0][0]=1;
for(int i=1;i<=n;i++){
int u=i&1,v=1-(i&1);
for(int j=0;j<=sum;j++){
for(int k=0;k<=num[i]&&k*val[i]+j<=sum;k++){
f[j+k*val[i]][u]+=f[j][v];
}
}
for(int j=0;j<=sum;j++){
f[j][v]=0;
}
}
for(int i=sum/2;i>=0;i--){
if(f[i][n&1]){
cout<<all-i<<" "<<i<<endl;
return;
}
}
}
int main(){
while(~scanf("%d",&n)){
if(n<0) return 0;
solve();
}
return 0;
}