• JAVA递归、非递归遍历二叉树(转)


    原文链接: JAVA递归、非递归遍历二叉树

     

    import java.util.Stack;  
    import java.util.HashMap;  
      
    public class BinTree {  
        private char date;  
        private BinTree lchild;  
        private BinTree rchild;  
      
        public BinTree(char c) {  
            date = c;  
        }  
      
        // 先序遍历递归   
        public static void preOrder(BinTree t) {  
            if (t == null) {  
                return;  
            }  
            System.out.print(t.date);  
            preOrder(t.lchild);  
            preOrder(t.rchild);  
        }  
      
        // 中序遍历递归   
        public static void InOrder(BinTree t) {  
            if (t == null) {  
                return;  
            }  
            InOrder(t.lchild);  
            System.out.print(t.date);  
            InOrder(t.rchild);  
        }  
      
        // 后序遍历递归   
        public static void PostOrder(BinTree t) {  
            if (t == null) {  
                return;  
            }  
            PostOrder(t.lchild);  
            PostOrder(t.rchild);  
            System.out.print(t.date);  
        }  
      
        // 先序遍历非递归   
        public static void preOrder2(BinTree t) {  
            Stack<BinTree> s = new Stack<BinTree>();  
            while (t != null || !s.empty()) {  
                while (t != null) {  
                    System.out.print(t.date);  
                    s.push(t);  
                    t = t.lchild;  
                }  
                if (!s.empty()) {  
                    t = s.pop();  
                    t = t.rchild;  
                }  
            }  
        }  
      
        // 中序遍历非递归   
        public static void InOrder2(BinTree t) {  
            Stack<BinTree> s = new Stack<BinTree>();  
            while (t != null || !s.empty()) {  
                while (t != null) {  
                    s.push(t);  
                    t = t.lchild;  
                }  
                if (!s.empty()) {  
                    t = s.pop();  
                    System.out.print(t.date);  
                    t = t.rchild;  
                }  
            }  
        }  
      
        // 后序遍历非递归   
        public static void PostOrder2(BinTree t) {  
            Stack<BinTree> s = new Stack<BinTree>();  
            Stack<Integer> s2 = new Stack<Integer>();  
            Integer i = new Integer(1);  
            while (t != null || !s.empty()) {  
                while (t != null) {  
                    s.push(t);  
                    s2.push(new Integer(0));  
                    t = t.lchild;  
                }  
                while (!s.empty() && s2.peek().equals(i)) {  
                    s2.pop();  
                    System.out.print(s.pop().date);  
                }  
      
                if (!s.empty()) {  
                    s2.pop();  
                    s2.push(new Integer(1));  
                    t = s.peek();  
                    t = t.rchild;  
                }  
            }  
        }  
      
        public static void main(String[] args) {  
            BinTree b1 = new BinTree('a');  
            BinTree b2 = new BinTree('b');  
            BinTree b3 = new BinTree('c');  
            BinTree b4 = new BinTree('d');  
            BinTree b5 = new BinTree('e');  
      
            /** 
             *      a  
             *     / / 
             *    b   c 
             *   / / 
             *  d   e 
             */  
            b1.lchild = b2;  
            b1.rchild = b3;  
            b2.lchild = b4;  
            b2.rchild = b5;  
      
            BinTree.preOrder(b1);  
            System.out.println();  
            BinTree.preOrder2(b1);  
            System.out.println();  
            BinTree.InOrder(b1);  
            System.out.println();  
            BinTree.InOrder2(b1);  
            System.out.println();  
            BinTree.PostOrder(b1);  
            System.out.println();  
            BinTree.PostOrder2(b1);  
        }  
    }  
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  • 原文地址:https://www.cnblogs.com/gaopeng527/p/5451176.html
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