Given a binary tree containing digits from 0-9
only, each root-to-leaf path could represent a number.
An example is the root-to-leaf path 1->2->3
which represents the number 123
.
Find the total sum of all root-to-leaf numbers.
For example,
1 / 2 3
The root-to-leaf path 1->2
represents the number 12
.
The root-to-leaf path 1->3
represents the number 13
.
Return the sum = 12 + 13 = 25
.
1 /** 2 * Definition for binary tree 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 public int sumNumbers(TreeNode root) { 12 // Start typing your Java solution below 13 // DO NOT write main() function 14 if(root == null){ 15 return 0; 16 } 17 ArrayList<String> result = new ArrayList<String>(); 18 StringBuilder sb = new StringBuilder(); 19 int sum = 0; 20 dfs(root, sb, result); 21 for(int i = 0; i < result.size(); i++){ 22 sum += Integer.parseInt(result.get(i)); 23 } 24 return sum; 25 } 26 27 public void dfs(TreeNode root, StringBuilder sb, ArrayList<String> result){ 28 if(root.left == null && root.right == null){ 29 sb.append(root.val); 30 result.add(sb.toString()); 31 sb.deleteCharAt(sb.length() - 1); 32 return; 33 } 34 sb.append(root.val); 35 if(root.left != null){ 36 //sb.append(root.left.val); 37 dfs(root.left, sb, result); 38 //sb.deleteCharAt(sb.length() - 1); 39 } 40 if(root.right != null){ 41 //sb.append(root.right.val); 42 dfs(root.right, sb, result); 43 //sb.deleteCharAt(sb.length() - 1); 44 } 45 sb.deleteCharAt(sb.length() - 1); 46 } 47 }