简单来说,就是小的数组的元素是不是都是大的数组里面的
arr1: [1,2,3]
arr2: [3,4,5,1,3,2]
输出true
arr1: [1,2,3,3]
arr2: [3,4,5,1,3,2]
输出true
function isSubArr(a,b) {
let big = []
let small = []
let set = new Set()
if (a.length >= b.length) {
big = a
small = b
} else {
big = b
small = a
}
for (let item of big) {
set.add(item)
}
for (let i = 0; i < small.length; i++) {
if (!set.has(small[i])) {
return false
}
}
return true
}
function isSubArr(a,b) {
let big = []
let small = []
if (a.length >= b.length) {
big = a
small = b
} else {
big = b
small = a
}
small = small.sort((a,b) => a - b)
big = big.sort((a,b) => a - b)
let slen = small.length
let blen = big.length
let i = 0, j = 0;
while(i < slen && j < blen) {
if (small[i] > big[j]) {
if (j == blen - 1) {
return false
} else {
j++
}
} else if (small[i] === b[j]) {
i++
j++
while(i < slen && j < blen && small[i] === small[i - 1]) {
i++
}
while(i < slen && j < blen && big[j] === big[j - 1]) {
j++
}
} else {
return false
}
}
return true
}