• C# 人民币大写金额转换


    /// <summary> 
         /// 转换人民币大小金额 
         /// </summary> 
         /// <param name="num">金额</param> 
         /// <returns>返回大写形式</returns> 
         public static string CmycurD(decimal num)
         {
             string str1 = "零壹贰叁肆伍陆柒捌玖";            //0-9所对应的汉字 
             string str2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"; //数字位所对应的汉字 
             string str3 = "";    //从原num值中取出的值 
             string str4 = "";    //数字的字符串形式 
             string str5 = "";  //人民币大写金额形式 
             int i;    //循环变量 
             int j;    //num的值乘以100的字符串长度 
             string ch1 = "";    //数字的汉语读法 
             string ch2 = "";    //数字位的汉字读法 
             int nzero = 0;  //用来计算连续的零值是几个 
             int temp;            //从原num值中取出的值 
     
             num = Math.Round(Math.Abs(num), 2);    //将num取绝对值并四舍五入取2位小数 
             str4 = ((long)(num * 100)).ToString();        //将num乘100并转换成字符串形式 
             j = str4.Length;      //找出最高位 
             if (j > 15) { return "溢出"; }
             str2 = str2.Substring(15 - j);   //取出对应位数的str2的值。如:200.55,j为5所以str2=佰拾元角分 
     
             //循环取出每一位需要转换的值 
             for (i = 0; i < j; i++)
             {
                 str3 = str4.Substring(i, 1);          //取出需转换的某一位的值 
                 temp = Convert.ToInt32(str3);      //转换为数字 
                 if (i != (j - 3) && i != (j - 7) && i != (j - 11) && i != (j - 15))
                 {
                     //当所取位数不为元、万、亿、万亿上的数字时 
                     if (str3 == "0")
                     {
                         ch1 = "";
                         ch2 = "";
                         nzero = nzero + 1;
                     }
                     else
                     {
                         if (str3 != "0" && nzero != 0)
                         {
                             ch1 = "零" + str1.Substring(temp * 1, 1);
                             ch2 = str2.Substring(i, 1);
                             nzero = 0;
                         }
                         else
                         {
                             ch1 = str1.Substring(temp * 1, 1);
                             ch2 = str2.Substring(i, 1);
                             nzero = 0;
                         }
                     }
                 }
                 else
                 {
                     //该位是万亿,亿,万,元位等关键位 
                     if (str3 != "0" && nzero != 0)
                     {
                         ch1 = "零" + str1.Substring(temp * 1, 1);
                         ch2 = str2.Substring(i, 1);
                         nzero = 0;
                     }
                     else
                     {
                         if (str3 != "0" && nzero == 0)
                         {
                             ch1 = str1.Substring(temp * 1, 1);
                             ch2 = str2.Substring(i, 1);
                             nzero = 0;
                         }
                         else
                         {
                             if (str3 == "0" && nzero >= 3)
                             {
                                 ch1 = "";
                                 ch2 = "";
                                 nzero = nzero + 1;
                             }
                             else
                             {
                                 if (j >= 11)
                                 {
                                     ch1 = "";
                                     nzero = nzero + 1;
                                 }
                                 else
                                 {
                                     ch1 = "";
                                     ch2 = str2.Substring(i, 1);
                                     nzero = nzero + 1;
                                 }
                             }
                         }
                     }
                 }
                 if (i == (j - 11) || i == (j - 3))
                 {
                     //如果该位是亿位或元位,则必须写上 
                     ch2 = str2.Substring(i, 1);
                 }
                 str5 = str5 + ch1 + ch2;
     
                 if (i == j - 1 && str3 == "0")
                 {
                     //最后一位(分)为0时,加上“整” 
                     str5 = str5 + '整';
                 }
             }
             if (num == 0)
             {
                 str5 = "零元整";
             }
             return str5;
         }
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  • 原文地址:https://www.cnblogs.com/fanying/p/10918975.html
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