现场编码题目3

现场编码题目3

有一个蓝色圆形游泳池，中间有两个黄色圆形岛，也就是说，下方图中有3个圆形图像,圆形半径分别为:最大的外圆半径为outR,岛1半径为inR1,岛2半径为inR2。求游泳池水域的面积。算法规则规定:必须采用面向对象技术，解决这个问题。

 参考代码 C#版:

using System;

namespace Case3
{
    class Circle
    {
        private int radius;
        public Circle(int r)
        {
            radius = r;
        }
        public double GetArea()
        {
            return 3.14 * radius * radius;
        }
    }

    class Program
    {
        static void Main(string[] args)
        {
            Console.WriteLine("Outer Circle Radius:");
            int outR=int.Parse(Console.ReadLine());
            Console.WriteLine("Inner Circle One Radius:");
            int inR1 = int.Parse(Console.ReadLine());
            Console.WriteLine("Inner Circle two Radius:");
            int  inR2 = int.Parse(Console.ReadLine());

            Circle outCircle = new Circle(outR);
            Circle inCircle1 = new Circle(inR1);
            Circle inCircle2 = new Circle(inR2);

            double actualArea = outCircle.GetArea() - inCircle1.GetArea() - inCircle2.GetArea();
            Console.WriteLine("Swimming Pool Actual Area:{0}", actualArea);        
        }
    }
}

参考代码 C++:

#include <iostream>
#include<algorithm>
using namespace std;

class Circle
{
public:
    Circle(int r);
    double GetArea();
private:
    int radius;
};

Circle::Circle(int r) 
{
    radius = r;
}
double Circle::GetArea()
{
    return 3.14 * radius * radius;
}

int main()
{
    float  outR, inR1, inR2;
    cout << "Outer Circle Radius:"<<endl;
    cin >> outR;
    cout << "Inner Circle One Radius:"<<endl;
    cin >> inR1;
    cout << "Inner Circle two Radius:"<<endl;
    cin >> inR2;
    Circle outCircle = Circle(outR);
    Circle inCircle1 = Circle(inR1);
    Circle inCircle2 = Circle(inR2);
    double actualArea = outCircle.GetArea() - inCircle1.GetArea() - inCircle2.GetArea();
    cout << "Swimming Pool Actual Area :" << actualArea << endl;

}

参考代码 Python版:

class Cirlce:
    def __init__(self,r):
        self.r=r

    def GetArea(self):
        return self.r*self.r*3.14


outR=int(input("Outer Circle Radius:"))
inR1=int(input("Inner Circle one Radius:"))
inR2=int(input("Inner Circle two Radius:"))

outCircle=Cirlce(outR)
inCircle1=Cirlce(inR1)
inCircle2=Cirlce(inR2)

actualArea=outCircle.GetArea()-inCircle1.GetArea()-inCircle2.GetArea()
print("Swimming Pool Actual Area:",actualArea)