• 【POJ 1679】 The Unique MST


    【题目链接】

                 点击打开链接

    【算法】

               先求出图的最小生成树

               枚举不在最小生成树上的边,若加入这条边,则形成了一个环,如果在环上且在最小生成树上的权值最大的边等于

               这条边的权值,那么,显然最小生成树不唯一

               树上倍增可以解决这个问题

    【代码】

               

    #include <algorithm>
    #include <bitset>
    #include <cctype>
    #include <cerrno>
    #include <clocale>
    #include <cmath>
    #include <complex>
    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <ctime>
    #include <deque>
    #include <exception>
    #include <fstream>
    #include <functional>
    #include <limits>
    #include <list>
    #include <map>
    #include <iomanip>
    #include <ios>
    #include <iosfwd>
    #include <iostream>
    #include <istream>
    #include <ostream>
    #include <queue>
    #include <set>
    #include <sstream>
    #include <stdexcept>
    #include <streambuf>
    #include <string>
    #include <utility>
    #include <vector>
    #include <cwchar>
    #include <cwctype>
    #include <stack>
    #include <limits.h>
    using namespace std;
    #define MAXN 110
    #define MAXM 1000010
    #define MAXLOG 20
    
    struct Edge
    {
            int x,y;
            long long w;
    } edge[MAXM];
    
    int T,n,m,i;
    long long val;
    vector< pair<int,long long> > e[MAXN];
    bool on_mst[MAXM];
    int fa[MAXN],anc[MAXN][MAXLOG],dep[MAXN];
    long long mx[MAXN][MAXLOG];
    bool not_unique;
    
    inline bool cmp(Edge a,Edge b) { return a.w < b.w; }
    inline int get_root(int x)
    {
            if (fa[x] == x) return x;
            return fa[x] = get_root(fa[x]);
    }
    inline void kruskal()
    {
            int i,x,y,sx,sy;
            long long w;
            for (i = 1; i <= n; i++) fa[i] = i;
            for (i = 1; i <= m; i++) on_mst[i] = false;
            sort(edge+1,edge+m+1,cmp);
            for (i = 1; i <= m; i++)
            {
                    x = edge[i].x;
                    y = edge[i].y;
                    w = edge[i].w;
                    sx = get_root(x); 
                    sy = get_root(y);
                    if (sx != sy)
                    {
                            on_mst[i] = true;
                            val += w;
                            fa[sx] = sy;
                            e[x].push_back(make_pair(y,w));
                            e[y].push_back(make_pair(x,w));    
                    }    
            }    
    }
    inline void build(int u)
    {
            int i,v;
            for (i = 1; i < MAXLOG; i++) 
            {
                    anc[u][i] = anc[anc[u][i-1]][i-1];
                    mx[u][i] = max(mx[u][i-1],mx[anc[u][i-1]][i-1]);
            }
            for (i = 0; i < e[u].size(); i++)
            {
                    v = e[u][i].first;
                    if (anc[u][0] != v)
                    {
                            dep[v] = dep[u] + 1;
                            anc[v][0] = u;
                            mx[v][0] = e[u][i].second;
                            build(v);                        
                    }
            }
    }
    inline long long get(int x,int y)
    {
            int i,t;
            long long ans = 0;
            if (dep[x] > dep[y]) swap(x,y);
            t = dep[y] - dep[x];
            for (i = 0; i < MAXLOG; i++)
            {
                    if (t & (1 << i))
                    {
                            ans = max(ans,mx[y][i]);
                            y = anc[y][i];
                    }
            }
            if (x == y) return ans;
            for (i = MAXLOG - 1; i >= 0; i--)
            {
                    if (anc[x][i] != anc[y][i])
                    {
                            ans = max(ans,max(mx[x][i],mx[y][i]));
                            x = anc[x][i];
                            y = anc[y][i];
                    }
            }
            return max(ans,max(mx[x][0],mx[y][0]));
    }
    int main() 
    {
            
            scanf("%d",&T);
            while (T--)
            {
                    scanf("%d%d",&n,&m);
                    val = 0;
                    not_unique = false;
                    for (i = 1; i <= n; i++) 
                    {
                            dep[i] = 0;
                            e[i].clear();
                            memset(anc[i],0,sizeof(anc[i]));
                            memset(mx[i],0,sizeof(mx[i]));
                    }
                    for (i = 1; i <= m; i++) scanf("%d%d%lld",&edge[i].x,&edge[i].y,&edge[i].w);
                    kruskal();
                    build(1);
                    for (i = 1; i <= m; i++) 
                    {
                            if (!on_mst[i]) 
                                    not_unique |= (get(edge[i].x,edge[i].y) == edge[i].w);
                    }
                    if (not_unique) printf("Not Unique!
    "); 
                    else printf("%lld
    ",val);
            }
            
            return 0;
        
    }
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  • 原文地址:https://www.cnblogs.com/evenbao/p/9196289.html
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