• HDOJ1128 Self Numbers


    Self Numbers

    Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 4487    Accepted Submission(s): 1961


    Problem Description
    In 1949 the Indian mathematician D.R. Kaprekar discovered a class of numbers called self-numbers. For any positive integer n, define d(n) to be n plus the sum of the digits of n. (The d stands for digitadition, a term coined by Kaprekar.) For example, d(75) = 75 + 7 + 5 = 87. Given any positive integer n as a starting point, you can construct the infinite increasing sequence of integers n, d(n), d(d(n)), d(d(d(n))), .... For example, if you start with 33, the next number is 33 + 3 + 3 = 39, the next is 39 + 3 + 9 = 51, the next is 51 + 5 + 1 = 57, and so you generate the sequence
    33, 39, 51, 57, 69, 84, 96, 111, 114, 120, 123, 129, 141, ...

    The number n is called a generator of d(n). In the sequence above, 33 is a generator of 39, 39 is a generator of 51, 51 is a generator of 57, and so on. Some numbers have more than one generator: for example, 101 has two generators, 91 and 100. A number with no generators is a self-number. There are thirteen self-numbers less than 100: 1, 3, 5, 7, 9, 20, 31, 42, 53, 64, 75, 86, and 97.


    Write a program to output all positive self-numbers less than or equal 1000000 in increasing order, one per line.
     
    Sample Output
    1 3 5 7 9 20 31 42 53 64 | | <-- a lot more numbers | 9903 9914 9925 9927 9938 9949 9960 9971 9982 9993 | | |
     
     
     1 #include<stdio.h>
     2 int flag[1000001];
     3 
     4 int fun(int i)
     5 {
     6     int t=i;
     7     while(t)
     8     {
     9         i+=t%10;
    10         t/=10;
    11     }
    12     return i;
    13 }
    14 
    15 int main()
    16 {
    17     int i;
    18     //freopen("1.text","w",stdout); 
    19     for(i=1;i<1000001;++i)
    20     {
    21         flag[fun(i)]=1;
    22     }
    23     for(i=1;i<1000001;++i)
    24         if(flag[i]==0)
    25             printf("%d\n",i);
    26         return 0;
    27 }
    功不成,身已退
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  • 原文地址:https://www.cnblogs.com/dongsheng/p/2647053.html
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