| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 23885 | Accepted: 10653 |
Description
Standard web browsers contain features to move backward and forward among the pages recently visited. One way to implement these features is to use two stacks to keep track of the pages that can be reached by moving backward and forward. In this problem, you are asked to implement this.
The following commands need to be supported:
BACK: Push the current page on the top of the forward stack. Pop the page from the top of the backward stack, making it the new current page. If the backward stack is empty, the command is ignored.
FORWARD: Push the current page on the top of the backward stack. Pop the page from the top of the forward stack, making it the new current page. If the forward stack is empty, the command is ignored.
VISIT : Push the current page on the top of the backward stack, and make the URL specified the new current page. The forward stack is emptied.
QUIT: Quit the browser.
Assume that the browser initially loads the web page at the URL http://www.acm.org/
The following commands need to be supported:
BACK: Push the current page on the top of the forward stack. Pop the page from the top of the backward stack, making it the new current page. If the backward stack is empty, the command is ignored.
FORWARD: Push the current page on the top of the backward stack. Pop the page from the top of the forward stack, making it the new current page. If the forward stack is empty, the command is ignored.
VISIT : Push the current page on the top of the backward stack, and make the URL specified the new current page. The forward stack is emptied.
QUIT: Quit the browser.
Assume that the browser initially loads the web page at the URL http://www.acm.org/
Input
Input is a sequence of commands. The command keywords BACK, FORWARD, VISIT, and QUIT are all in uppercase. URLs have no whitespace and have at most 70 characters. You may assume that no problem instance requires more than 100 elements in each stack at any time. The end of input is indicated by the QUIT command.
Output
For each command other than QUIT, print the URL of the current page after the command is executed if the command is not ignored. Otherwise, print "Ignored". The output for each command should be printed on its own line. No output is produced for the QUIT command.
Sample Input
VISIT http://acm.ashland.edu/ VISIT http://acm.baylor.edu/acmicpc/ BACK BACK BACK FORWARD VISIT http://www.ibm.com/ BACK BACK FORWARD FORWARD FORWARD QUIT
Sample Output
http://acm.ashland.edu/ http://acm.baylor.edu/acmicpc/ http://acm.ashland.edu/ http://www.acm.org/ Ignored http://acm.ashland.edu/ http://www.ibm.com/ http://acm.ashland.edu/ http://www.acm.org/ http://acm.ashland.edu/ http://www.ibm.com/ Ignored
/*
功能Function Description: 栈的应用 POJ-1028 TOJ-1196
开发环境Environment: DEV C++ 4.9.9.1
技术特点Technique:
版本Version:
作者Author: 可笑痴狂
日期Date: 20120802
备注Notes: 栈也可以存储定义string类型
题目来源：
*/
#include<iostream>
#include<string>
#include<stack>
using namespace std;
int main()
{
stack<string> s1,s2;
string cmd,URL;
s1.push("http://www.acm.org/");
while(cin>>cmd)
{
if(cmd[0]=='Q')
break;
else if(cmd[0]=='V')
{
cin>>URL;
s1.push(URL);
cout<<URL<<endl;
while(!s2.empty()) //注意这里要将s2清空
s2.pop();
}
else if(cmd[0]=='B')
{
if(s1.size()>1) //注意这里是大于1，即必须有两个或两个以上元素才行，
{ //因为s1的栈顶元素是当前访问的页面，后退一步必须返回到当前栈顶的下一个元素
s2.push(s1.top());
s1.pop();
cout<<s1.top()<<endl;
}
else
cout<<"Ignored"<<endl;
}
else
{
if(!s2.empty())
{
s1.push(s2.top());
cout<<s2.top()<<endl;
s2.pop();
}
else
cout<<"Ignored"<<endl;
}
}
return 0;
}