• 【小米oj】 需要多少个立方数


     1 #define mm(a) memset(a,0,sizeof(a));
     2 #define max(x,y) (x)>(y)?(x):(y)
     3 #define min(x,y) (x)<(y)?(x):(y)
     4 #define Fopen freopen("1.in","r",stdin); freopen("m.out","w",stdout);
     5 #define rep(i,a,b) for(int i=(a);i<=(b);i++)
     6 #define per(i,b,a) for(int i=(b);i>=(a);i--)
     7 #include<bits/stdc++.h>
     8 typedef long long ll;
     9 #define PII pair<int,int>
    10 using namespace std;
    11 const int INF=0x3f3f3f3f;
    12 const int MAXN=(int)1e6 + 5;
    13 const ll mod=1e9+7;
    14 
    15 
    16 int n;
    17 bool vis[MAXN];
    18 queue<pair<int, int>> q;
    19 int gao(int n) {
    20     while(!q.empty())q.pop();
    21     mm(vis);
    22     q.push(make_pair(n, 0));
    23     vis[n]=1;
    24     while(!q.empty()) {
    25         PII now=q.front();
    26         q.pop();
    27         if (now.first==0) return now.second;
    28         for (int i=1; i*i*i<=now.first; i++) {
    29             int a=now.first-i*i*i;
    30             if (a==0)return now.second+1;
    31             if (!vis[a]) {
    32                 q.push(make_pair(a,now.second+1));
    33                 vis[a]=1;
    34             }
    35         }
    36     }
    37 }
    38 
    39 int main() {
    40     while(~scanf("%d",&n))printf("%d
    ",gao(n));
    41     return 0;
    42 }
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  • 原文地址:https://www.cnblogs.com/dogenya/p/10815612.html
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