• LeetCode_104. Maximum Depth of Binary Tree


    104. Maximum Depth of Binary Tree

    Easy

    Given a binary tree, find its maximum depth.

    The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

    Note: A leaf is a node with no children.

    Example:

    Given binary tree [3,9,20,null,null,15,7],

        3
       / 
      9  20
        /  
       15   7

    return its depth = 3.

    package leetcode.easy;
    
    /**
     * Definition for a binary tree node. public class TreeNode { int val; TreeNode
     * left; TreeNode right; TreeNode(int x) { val = x; } }
     */
    public class MaximumDepthOfBinaryTree {
    	public int maxDepth(TreeNode root) {
    		if (null == root) {
    			return 0;
    		} else if (null == root.left) {
    			return 1 + maxDepth(root.right);
    		} else if (null == root.right) {
    			return 1 + maxDepth(root.left);
    		} else {
    			return 1 + Math.max(maxDepth(root.left), maxDepth(root.right));
    		}
    	}
    
    	@org.junit.Test
    	public void test() {
    		TreeNode tn11 = new TreeNode(3);
    		TreeNode tn21 = new TreeNode(9);
    		TreeNode tn22 = new TreeNode(20);
    		TreeNode tn33 = new TreeNode(15);
    		TreeNode tn34 = new TreeNode(7);
    		tn11.left = tn21;
    		tn11.right = tn22;
    		tn21.left = null;
    		tn21.right = null;
    		tn22.left = tn33;
    		tn22.right = tn34;
    		tn33.left = null;
    		tn33.right = null;
    		tn34.left = null;
    		tn34.right = null;
    		System.out.println(maxDepth(tn11));
    	}
    }
    
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  • 原文地址:https://www.cnblogs.com/denggelin/p/11608134.html
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