• java集合-HashMap(JDK1.8)


    一、基本概念

    HashMap基于哈希表的 Map 接口的实现。此实现提供所有可选的映射操作,并允许使用 null 值和 null 键。以前JDK中HashMap采用的是位桶+链表的方式,即我们常说的散列链表的方式,而JDK1.8中采用的是位桶+链表/红黑树的方式,也是非线程安全的。当某个位桶的链表的长度达到某个阀值的时候,这个链表就将转换成红黑树。
    注意事项:

    1. HashMap 是一个散列表,它存储的内容是键值对(key-value)映射;
    2. HashMap 继承于AbstractMap,实现了Map、Cloneable、java.io.Serializable接口;
    3. HashMap 的实现不是同步的,这意味着它不是线程安全的。它的key、value都可以为null;
    4. HashMap中的映射不是有序的;
    5. HashMap 的实例有两个参数影响其性能:“初始容量” 和 “加载因子”;

    二、源码分析

    1:常量

       /**
       map的最大容量
         */
        static final int MAXIMUM_CAPACITY = 1 << 30;
    
        /**
         * 默认加载因子
         */
        static final float DEFAULT_LOAD_FACTOR = 0.75f;
    
        /**
         将list链表转为红黑数阀值,即list的size超过时转化
         */
        static final int TREEIFY_THRESHOLD = 8;
    
        /**
         resize操作中,决定是否untreeify的阈值
         */
        static final int UNTREEIFY_THRESHOLD = 6;
    
        /**
         决定是否转换成tree的最小容量
         */
        static final int MIN_TREEIFY_CAPACITY = 64;
    
    

    2:主要字段

    /**
    存储元素的数组
    */
     transient Node<K,V>[] table;
     /**
     用于map迭代遍历
     */
     transient Set<Map.Entry<K,V>> entrySet;
    
        /**
         元素个数
         */
        transient int size;
    
        /**
         修改次数
         */
        transient int modCount;
    
        /**
        阀值,用于扩容阀值
         */
        int threshold;
    
        /**
         加载因子
         */
        final float loadFactor;
    

    3:主要方法
    get方法:

    public V get(Object key) {
            Node<K,V> e;
            return (e = getNode(hash(key), key)) == null ? null : e.value;
        }
    
        /**
         * Implements Map.get and related methods
         *
         * @param hash hash for key
         * @param key the key
         * @return the node, or null if none
         */
        final Node<K,V> getNode(int hash, Object key) {
            Node<K,V>[] tab; Node<K,V> first, e; int n; K k;
            if ((tab = table) != null && (n = tab.length) > 0 &&
                (first = tab[(n - 1) & hash]) != null) {
                if (first.hash == hash && // 总是判断第一个元素是否满足条件
                    ((k = first.key) == key || (key != null && key.equals(k))))
                    return first;
                if ((e = first.next) != null) {
                //第一个节点为TreeNode,则调用TreeNode.getTreeNode()方法遍历红黑数进行查询
                    if (first instanceof TreeNode)
                        return ((TreeNode<K,V>)first).getTreeNode(hash, key);
                    do {
                        if (e.hash == hash &&
                            ((k = e.key) == key || (key != null && key.equals(k))))
                            return e;
                    } while ((e = e.next) != null);
                }
            }
            return null;
        }
    

    put方法

    public V put(K key, V value) {
            return putVal(hash(key), key, value, false, true);
        }
    
        /**
         * Implements Map.put and related methods
         *
         * @param hash hash for key
         * @param key the key
         * @param value the value to put
         * @param onlyIfAbsent if true, don't change existing value
         * @param evict if false, the table is in creation mode.
         * @return previous value, or null if none
         */
        final V putVal(int hash, K key, V value, boolean onlyIfAbsent,
                       boolean evict) {
            Node<K,V>[] tab; Node<K,V> p; int n, i;
            if ((tab = table) == null || (n = tab.length) == 0)
            //table为空,n为table的长度
                n = (tab = resize()).length;
                //i位置为空,直接存储
            if ((p = tab[i = (n - 1) & hash]) == null)
                tab[i] = newNode(hash, key, value, null);
            else {
            // 若i位置上的值不为空,判断当前位置上的Node p 是否与要插入的key的hash和key相同
                Node<K,V> e; K k;
                if (p.hash == hash &&
                    ((k = p.key) == key || (key != null && key.equals(k))))
                    //相同key时直接覆盖
                    e = p;
                else if (p instanceof TreeNode)
                //不相同时,若当前p已经为TreeNode,则插入该树上
                    e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
                else {
                //在i位置上的链表中找到p.next为null的位置,binCount计算出当前链表的长度,如果继续将冲突的节点插入到该链表中,会使链表的长度大于tree化的阈值,则将链表转换成tree。
                    for (int binCount = 0; ; ++binCount) {
                        if ((e = p.next) == null) {
                            p.next = newNode(hash, key, value, null);
                            if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
                                treeifyBin(tab, hash);
                            break;
                        }
                        if (e.hash == hash &&
                            ((k = e.key) == key || (key != null && key.equals(k))))
                            break;
                        p = e;
                    }
                }
                if (e != null) { // existing mapping for key
                    V oldValue = e.value;
                    if (!onlyIfAbsent || oldValue == null)
                        e.value = value;
                    afterNodeAccess(e);
                    return oldValue;
                }
            }
            ++modCount;
            if (++size > threshold)
                resize();
            afterNodeInsertion(evict);
            return null;
        }
    

    resize(),由于解决冲突的方法可能是list,也可能是红黑数,所以resize()较为复杂点。

    /**
         * Initializes or doubles table size.  If null, allocates in
         * accord with initial capacity target held in field threshold.
         * Otherwise, because we are using power-of-two expansion, the
         * elements from each bin must either stay at same index, or move
         * with a power of two offset in the new table.
         *
         * @return the table
         */
        final Node<K,V>[] resize() {
            Node<K,V>[] oldTab = table;
            int oldCap = (oldTab == null) ? 0 : oldTab.length;
            int oldThr = threshold;
            int newCap, newThr = 0;
            if (oldCap > 0) {
            //若超过最大容量,则不能扩容
                if (oldCap >= MAXIMUM_CAPACITY) {
                    threshold = Integer.MAX_VALUE;
                    return oldTab;
                }
                else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY &&
                         oldCap >= DEFAULT_INITIAL_CAPACITY)
                    newThr = oldThr << 1; //阀值扩大2倍 
            }
            else if (oldThr > 0) // initial capacity was placed in threshold
                newCap = oldThr;
            else {               // zero initial threshold signifies using defaults
                newCap = DEFAULT_INITIAL_CAPACITY;
                newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY);
            }
            if (newThr == 0) {
                float ft = (float)newCap * loadFactor;
                newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ?
                          (int)ft : Integer.MAX_VALUE);
            }
            threshold = newThr;
            @SuppressWarnings({"rawtypes","unchecked"})
            // 创建容量为newCap的newTab,并将oldTab中的Node迁移过来,这里需要考虑链表和tree两种情况。
                Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
            table = newTab;
            if (oldTab != null) {
                for (int j = 0; j < oldCap; ++j) {
                    Node<K,V> e;
                    if ((e = oldTab[j]) != null) {
                        oldTab[j] = null;
                        if (e.next == null)
                            newTab[e.hash & (newCap - 1)] = e;
                        else if (e instanceof TreeNode)
                        // split方法会将树分割为lower 和upper tree两个树,如果子树的节点数小于了UNTREEIFY_THRESHOLD阈值,则将树untreeify,将节点都存放在newTab中。
                            ((TreeNode<K,V>)e).split(this, newTab, j, oldCap);
                        else { // preserve order
                            Node<K,V> loHead = null, loTail = null;
                            Node<K,V> hiHead = null, hiTail = null;
                            Node<K,V> next;
                            do {
                                next = e.next;
                                if ((e.hash & oldCap) == 0) {
                                    if (loTail == null)
                                        loHead = e;
                                    else
                                        loTail.next = e;
                                    loTail = e;
                                }
                                else {
                                    if (hiTail == null)
                                        hiHead = e;
                                    else
                                        hiTail.next = e;
                                    hiTail = e;
                                }
                            } while ((e = next) != null);
                            if (loTail != null) {
                                loTail.next = null;
                                newTab[j] = loHead;
                            }
                            if (hiTail != null) {
                                hiTail.next = null;
                                newTab[j + oldCap] = hiHead;
                            }
                        }
                    }
                }
            }
            return newTab;
        }
    
    

    remove()方法

    public V remove(Object key) {
            Node<K,V> e;
            return (e = removeNode(hash(key), key, null, false, true)) == null ?
                null : e.value;
        }
    
        /**
         * Implements Map.remove and related methods
         *
         * @param hash hash for key
         * @param key the key
         * @param value the value to match if matchValue, else ignored
         * @param matchValue if true only remove if value is equal
         * @param movable if false do not move other nodes while removing
         * @return the node, or null if none
         */
        final Node<K,V> removeNode(int hash, Object key, Object value,
                                   boolean matchValue, boolean movable) {
            Node<K,V>[] tab; Node<K,V> p; int n, index;
            if ((tab = table) != null && (n = tab.length) > 0 &&
                (p = tab[index = (n - 1) & hash]) != null) {
                Node<K,V> node = null, e; K k; V v;
                if (p.hash == hash &&
                    ((k = p.key) == key || (key != null && key.equals(k))))
                    node = p;
                    //若是用红黑数解决冲突则getTreeNode方法查找到节点
                else if ((e = p.next) != null) {
                    if (p instanceof TreeNode)
                        node = ((TreeNode<K,V>)p).getTreeNode(hash, key);
                    else {
                        do {
                            if (e.hash == hash &&
                                ((k = e.key) == key ||
                                 (key != null && key.equals(k)))) {
                                node = e;
                                break;
                            }
                            p = e;
                        } while ((e = e.next) != null);
                    }
                }
                if (node != null && (!matchValue || (v = node.value) == value ||
                                     (value != null && value.equals(v)))) {
                    if (node instanceof TreeNode)
                        ((TreeNode<K,V>)node).removeTreeNode(this, tab, movable);
                    else if (node == p)
                        tab[index] = node.next;
                    else
                        p.next = node.next;
                    ++modCount;
                    --size;
                    afterNodeRemoval(node);
                    return node;
                }
            }
            return null;
        }
    

    HashMap实例

    1:Hashmap的遍历方法

    package com.csu.collection;
    
    import java.util.HashMap;
    import java.util.Iterator;
    import java.util.Map.Entry;
    import java.util.Set;
    
    public class HashMapTest {
    	
    	public static void main(String[]args)
    	{
    		HashMap<Integer, Integer> map=new HashMap<>();
    		for(int i=0;i<10000000;i++)
    		{
    			map.put(i, i);
    		}
    		System.out.println("第一种遍历方法:for each map.entrySet()");
    		long startTime1=System.currentTimeMillis();
    		for(Entry<Integer, Integer> entry:map.entrySet())
    		{
    			entry.getValue();
    			entry.getKey();
    		}
    		long endTime1=System.currentTimeMillis();
    		System.out.println("第一种遍历方法用时:"+(endTime1-startTime1)+"ms");
    		System.out.println("第2种遍历方法:map.entrySet()的集合迭代器");
    		long startTime2=System.currentTimeMillis();
    		Iterator<Entry<Integer, Integer>> iterator=map.entrySet().iterator();
    		while(iterator.hasNext())
    		{
    			HashMap.Entry<Integer, Integer> entry=(Entry<Integer, Integer>) iterator.next();
    			entry.getValue();
    			entry.getKey();
    		}
    		long endTime2=System.currentTimeMillis();
    		System.out.println("第2种遍历方法用时:"+(endTime2-startTime2)+"ms");
    		System.out.println("第3种遍历方法: for each map.keySet(),再调用get获取");
    		long startTime3=System.currentTimeMillis();
    		for (Integer key : map.keySet()) {
    			map.get(key);
    		}
    		long endTime3=System.currentTimeMillis();
    		System.out.println("第3种遍历方法用时:"+(endTime3-startTime3)+"ms");
    		System.out.println("第4种遍历方法:for each map.entrySet(),用临时变量保存map.entrySet()");
    		long startTime4=System.currentTimeMillis();
    		Set<Entry<Integer, Integer>> entrySet = map.entrySet();
    		for (Entry<Integer, Integer> entry : entrySet) {
    			entry.getKey();
    			entry.getValue();
    		}
    		long endTime4=System.currentTimeMillis();
    		System.out.println("第4种遍历方法用时:"+(endTime4-startTime4)+"ms");
    	}
    }
    
    

    运行结果

    第一种遍历方法:for each map.entrySet()
    第一种遍历方法用时:71ms
    第2种遍历方法:map.entrySet()的集合迭代器
    第2种遍历方法用时:83ms
    第3种遍历方法: for each map.keySet(),再调用get获取
    第3种遍历方法用时:117ms
    第4种遍历方法:for each map.entrySet(),用临时变量保存map.entrySet()
    第4种遍历方法用时:84ms
    

    总结:

    1. a. HashMap的循环,如果既需要key也需要value,直接用for each map.entrySet();
    2. 如果只是遍历key而无需value的话,可以直接用for each map.keySet(),再调用get获取。
      2:使用Hashmap 实现缓存
    public class Student {
    	private String name;
    	private String address;
    	public Student(String name,String address)
    	{
    		this.address=address;
    		this.name=name;
    	}
    	public String getName() {
    		return name;
    	}
    	public void setName(String name) {
    		this.name = name;
    	}
    	public String getAddress() {
    		return address;
    	}
    	public void setAddress(String address) {
    		this.address = address;
    	}
    }
    
    
    import java.io.Serializable;
    
    public class CacheEntity implements Serializable {
    
    	/**
    	 * 
    	 */
    	private static final long serialVersionUID = 1L;
    	
    	private final int DEFUALT_TIME=200;//秒
    	
    	private String  key;
    	private Object value;
    	private int time;//缓存存活时间,不设置则使用默认值
    	private long timeoutStamp;// 缓存过期时间戳
    	
    	@SuppressWarnings("unused")
    	private CacheEntity()
    	{
    		this.timeoutStamp=System.currentTimeMillis()+DEFUALT_TIME*1000;
    		this.time=DEFUALT_TIME;
    	}
    	public CacheEntity(String key,Object value)
    	{
    		this.key=key;
    		this.value=value;
    	}
    	public CacheEntity(String key,Object value,long timestamp)
    	{
    		this(key,value);
    		this.timeoutStamp=timestamp;
    	}
    	public CacheEntity(String key,Object value,int time)
    	{
    		this(key,value);
    		this.time=time;
    		this.timeoutStamp=System.currentTimeMillis()+DEFUALT_TIME*1000;
    	}
    	public String getKey() {
    		return key;
    	}
    	public void setKey(String key) {
    		this.key = key;
    	}
    	public Object getValue() {
    		return value;
    	}
    	public void setValue(Object value) {
    		this.value = value;
    	}
    	public int getTime() {
    		return time;
    	}
    	public void setTime(int time) {
    		this.time = time;
    	}
    	public long getTimeoutStamp() {
    		return timeoutStamp;
    	}
    	public void setTimeoutStamp(long timeoutStamp) {
    		this.timeoutStamp = timeoutStamp;
    	}
    }
    
    
    import java.util.ArrayList;
    import java.util.HashMap;
    import java.util.List;
    
    /**
     * 
     * 采用队列,定时循环清理过期缓存
     *
     */
    public class CacheByHashMap {
    	
    	
    	private static  HashMap<String, CacheEntity> map;
    	private static List<CacheEntity> tempList;
    	static{
    		tempList=new ArrayList<CacheEntity>();
    		map=new HashMap<String,CacheEntity>(1<<10);	
    		new Thread(new RemoveTimeOutCacheThread()).start();
    		
    	}
      /**
       * 添加缓存
       * @param key
       * @param value
       * @param time
       */
    	public static synchronized void addCache(String key,CacheEntity value,int time)
    	{
    		value.setTimeoutStamp(System.currentTimeMillis()+time*1000);
    		map.put(key, value);
    		tempList.add(value);
    	}
    	/**
    	 * 获取缓存对象
    	 * @param key
    	 * @return
    	 */
    	public static synchronized CacheEntity getCache(String key)
    	{
    		return map.get(key);
    	}
    	/**
    	 * 检查是否包含特定的key
    	 * @param key
    	 * @return
    	 */
    	public static synchronized boolean isContainsKey(String key)
    	{
    		return map.containsKey(key);
    	}
    	/**
    	 * 删除缓存
    	 * @param key
    	 */
    	public static synchronized void removeCache(String key)
    	{
    		map.remove(key);
    	}
        /**
         *  获取缓存数量
         * @return
         */
    	public static int getCacheSize()
    	{
    	  return  map.size();
    	}
    	/**
    	 * 清除所有缓存
    	 */
    	public static synchronized void clearCache()
    	{
    		tempList.clear();
    		map.clear();
    		System.out.println("所有缓存被清理");
    	}
    	static class RemoveTimeOutCacheThread implements Runnable{
    
    		@Override
    		public void run() {
    			// TODO Auto-generated method stub
    			while(true)
    			{
    				try {
    					checkTime();
    				} catch (Exception e) {
    					// TODO: handle exception
    					e.printStackTrace();
    				}
    			}
    		}
    		
    		private void checkTime() throws InterruptedException
    		{
    			CacheEntity value=null;
    			long timeoutTime=1000l;
    			if(tempList.size()<1)
    			{
    				System.out.println("过期队列为空!");
    				timeoutTime=1000l;
    				Thread.sleep(timeoutTime);
    				return ;
    			}
    			value=tempList.get(0);
    			timeoutTime=value.getTimeoutStamp()-System.currentTimeMillis();
    			if(timeoutTime>0)
    			{
    				Thread.sleep(timeoutTime);
    				return ;
    			}
    			System.out.println("清除过期缓存"+value.getKey());
    			tempList.remove(value);
    			removeCache(value.getKey());
    		}
    		
    	}
    	
    }
    
    

    测试端代码:

    public class CacheTest {
    
    	public static void main(String[] args) {
    		// TODO Auto-generated method stub
    		Student student1=new Student("zhangsan", "shangsha");
    		Student student2=new Student("wangqiang", "beijing");
    		Student student3=new Student("zhangsi", "shanghai");
    		Student student4=new Student("zhangwu", "wuhan");
    		Student student5=new Student("zhangqi", "zhengzhou");
    		Student student6=new Student("zhangba", "shangsha");
    		CacheEntity cacheEntity1=new CacheEntity("1", student1, 30);
    		CacheEntity cacheEntity2=new CacheEntity("2", student2, 30);
    		CacheEntity cacheEntity3=new CacheEntity("3", student3, 30);
    		CacheEntity cacheEntity4=new CacheEntity("4", student4, 30);
    		CacheEntity cacheEntity5=new CacheEntity("5", student5, 30);
    		CacheEntity cacheEntity6=new CacheEntity("6", student6, 30);
    		//添加缓存
    		CacheByHashMap.addCache(cacheEntity1.getKey(), cacheEntity1, cacheEntity1.getTime());
    		CacheByHashMap.addCache(cacheEntity2.getKey(), cacheEntity2, cacheEntity2.getTime());
    		CacheByHashMap.addCache(cacheEntity3.getKey(), cacheEntity3, cacheEntity3.getTime());
    		CacheByHashMap.addCache(cacheEntity4.getKey(), cacheEntity4, cacheEntity4.getTime());
    		CacheByHashMap.addCache(cacheEntity5.getKey(), cacheEntity5, cacheEntity5.getTime());
    		CacheByHashMap.addCache(cacheEntity6.getKey(), cacheEntity6, cacheEntity6.getTime());
    		if(CacheByHashMap.isContainsKey("2"))
    		{
    			System.out.println(" 该对象已有缓存");
    			//这里就可以获取缓存如get()
    		}
    		else {
    			CacheByHashMap.addCache(cacheEntity2.getKey(), cacheEntity2, cacheEntity2.getTime());
    			//这里可以模拟从数据库获取数据,添加到缓存
    		}
    
    	}
    }
    
    

    运行结果:

    该对象已有缓存
    清除过期缓存1
    清除过期缓存2
    清除过期缓存3
    清除过期缓存4
    清除过期缓存5
    清除过期缓存6
    过期队列为空!
    过期队列为空!
    
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  • 原文地址:https://www.cnblogs.com/csuwater/p/5401533.html
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