Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
没什么好说的,把两个排好序的链表合成一个就行了
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if (!l1)return l2; if (!l2)return l1; ListNode *head,*current; if (l1->val < l2->val) { head = l1; l1 = l1->next; } else { head = l2; l2 = l2->next; } current = head; while (l1&&l2) { if (l1->val < l2->val) { current->next = l1; l1 = l1->next; } else { current->next = l2; l2 = l2->next; } current = current->next; } if (l1) { current->next = l1; } else current->next = l2; return head; } };