8.2.6 John

John

Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)

Total Submission(s): 31 Accepted Submission(s): 23

Problem Description

Little John is playing very funny game with his younger brother. There is one big box filled with M&Ms of different colors. At first John has to eat several M&Ms of the same color. Then his opponent has to make a turn. And so on. Please note that each player has to eat at least one M&M during his turn. If John (or his brother) will eat the last M&M from the box he will be considered as a looser and he will have to buy a new candy box.

Both of players are using optimal game strategy. John starts first always. You will be given information about M&Ms and your task is to determine a winner of such a beautiful game.

 

Input

The first line of input will contain a single integer T – the number of test cases. Next T pairs of lines will describe tests in a following format. The first line of each test will contain an integer N – the amount of different M&M colors in a box. Next line will contain N integers Ai, separated by spaces – amount of M&Ms of i-th color.

Constraints:
1 <= T <= 474,
1 <= N <= 47,
1 <= Ai <= 4747

 

Output

Output T lines each of them containing information about game winner. Print “John” if John will win the game or “Brother” in other case.

 

Sample Input

2
3
3 5 1
1
1

anti-nim

sg函数的题 给我写过的一篇sg函数的链接

http://www.cnblogs.com/cssystem/p/3204826.html

#include <cmath>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <string>
#include <cstdlib>
using namespace std;

const int maxn=210;
int n,ans,T,x;
bool flag;

void close()
{
exit(0);
}


void init()
{
    scanf("%d",&T);
    while (T--)
    {
        scanf("%d",&n);
        flag=false;
        scanf("%d",&ans);
        if (ans>1) flag=true;
        for (int i=2;i<=n;i++)
        {
            scanf("%d",&x);
            if (x>1) flag=true;
            ans=ans ^ x;
        }
        if (not flag) //全部是1
        {
            if (n % 2==0)
                printf("John
");
            else
                printf("Brother
");
        }
        else
        {        
            if (ans!=0)
                printf("John
");
            else
                printf("Brother
");
        }
    }
}

int main ()
{
    init();
    close();
    return 0;
}