golang unmarshal

my.xml中的内容如下：

<?xml version="1.0" encoding="UTF-8" ?>
<servers version="199">
    <server>
        <serverName>Shanghai_VPN</serverName>
        <serverIP>127.0.0.1</serverIP>
    </server>
    <server>
        <serverName>Beijing_VPN</serverName>
        <serverIP>127.0.0.2</serverIP>
    </server>
</servers>
实现代码如下：

package main

import (
   "encoding/xml"
   "fmt"
   "io/ioutil"
)

// 抽取单个server对象
type Server struct {
   ServerName string `xml:"serverName"`
   ServerIP   string `xml:"serverIP"`
}

/* https://golang.org/pkg/encoding/xml/#Unmarshal
* If the XMLName field has an associated tag of the form
"name" or "namespace-URL name", the XML element must have
the given name (and, optionally, name space) or else Unmarshal
returns an error.*/
type Servers struct {
   XMLName xml.Name `xml:"servers"` // 只有变量名字叫XMLName才能解析出来
   Version int      `xml:"version,attr"`
   Servers []Server `xml:"server"`
}

func main() {
   data, err := ioutil.ReadFile("./data_format/my.xml")
   if err != nil {
      fmt.Println(err)
      return
   }
   var servers = Servers{}
   err = xml.Unmarshal([]byte(data), &servers)
   if err != nil {
      fmt.Println(err)
      return
   }
   fmt.Println(servers.XMLName)
   fmt.Println(servers)
}
注意点：

结构体中标签的名字必须取名为XMLName，否则解析不出来。这是golang文档中的解释