• update语句更新多条记录, 标记下


    转 ---  的两篇内容

    View Code
    update多条Select出来的数据

    好多朋友喜欢用游标解决此问题,但是执行速度狂慢!
    其实解决起来很简单了:

    先来个简单的:
    把FLowER的Am_employee表的email,dept_id,ext_no多条数据按emp_no对应update到EmpBaseInfo表中:
    update EmpBaseInfo
    set email=b.Mail_account,dept_id=b.dept_code,ext_no=b.ext_no
    from flower.flower.dbo.am_employee b
    where b.emp_no=EmpBaseInfo.emp_no

    复杂一点的:
    多表select,并将结果对应插入到指定的表中:

    update EmpBaseInfo
    set Job_Rank=b.level_number
    from flower.flower.dbo.am_employee a,flower.flower.dbo.am_level b,flower.flower.dbo.am_approver_level c
    where a.emp_id=c.emp_id and b.level_number=c.level_number and a.emp_no=EmpBaseInfo.emp_no


    取别名的:
    update x
    set Job_Rank=b.level_number
    from flower.flower.dbo.am_employee a,flower.flower.dbo.am_level b,flower.flower.dbo.am_approver_level c,EmpBaseInfo x
    where a.emp_id=c.emp_id and b.level_number=c.level_number and a.emp_no=x.emp_no

    --另外一种方式: 临时表

    View Code
    偶用临时表来解决
    1、创建临时表#temp_1
    SELECT card_id,sum(card_cost) as 'sum_cost'
    INTO #tmp_1
    FROM pos_t_vip_cost
    GROUP by card_id
    go
    2、更新表pos_t_vip_info记录
    UPDATE pos_t_vip_info,#tmp_1
    SET pos_t_vip_info.card_amount = #tmp_1.sum_cost
    WHERE pos_t_vip_info.card_id = #tmp_1.card_id
    go
    3、删除临时表
    DROP TABLE #tmp_1
    go

    以上是参考资料

    View Code
    update [StormPlatform120316].[dbo].[t_Assessment]
    set Developers = le.DevelopmentPrincipal
    from [StormPlatform120316].[dbo].[t_Assessment] a left join [StormPlatform0623].[dbo].[t_LeaderEvaluation] le on a.RequirementApplyID = le.RequirementApplyID and le.createtime in (select max(createtime) from [StormPlatform0623].[dbo].[t_LeaderEvaluation] group by RequirementApplyID)
    where a.Developers = ''



    Mysql的update语句

    View Code
    2010-04-24 20:31 mysql update from 子查询mssql 子查询更新
    
    update log set uin= b.uin
    from log a,logs b
    where a.accountuin = b.accountuin
    
    mysql 不支持 update 子查询更新
    
    找了半天资料 终于搞定了...
    
    update `log` a inner join `logs` b on a.`accountuin` = b.`accountuin`
    set a.`uin` = b.`uin` where a.`accountuin` = b.`accountuin`
    
    这样就能 将查询出来的字段批量更新过去了...

    //delete的联合查询

    Update 
    
    
    Update XXX set XXX where 这种写法大家肯定都知道,才发现update和delete居然支持inner join的update方式,这个在表间关联来做更新和删除操作非常有用. 
    
    列子: 
    
    
    
    
    Sql代码 
    update tb_User   
    set pass=''  
    from tb_User usr   
    inner join tb_Address addr on usr.nAddressFK = addr.nAddressID   
    where usr.id=123  
    
    update tb_User 
    set pass='' 
    from tb_User usr 
    inner join tb_Address addr on usr.nAddressFK = addr.nAddressID 
    where usr.id=123update的格式是 
    
    update t1 set t1.name=’Liu’ from t1 inner join t2 on t1.id = t2.tid 
    
    
    
    
    MYSQL,ACCESS 写法如下: 
    
    
    
    
    Sql代码 
    UPDATE mem_world AS mw1 INNER JOIN mem_world  AS  mw2     
    ON  mw1.parentid = mw2.wid    
    SET mw1.level = mw2.level     
    WHERE mw2.baseid = 107     
    AND  mw2.parentid = 0     
    AND  mw2.size > 1;  
    
    UPDATE mem_world AS mw1 INNER JOIN mem_world  AS  mw2  
    ON  mw1.parentid = mw2.wid 
    SET mw1.level = mw2.level  
    WHERE mw2.baseid = 107  
    AND  mw2.parentid = 0  
    AND  mw2.size > 1; 
    
    on是表连接的筛选条件 
    就是说,表连接后,会产生一个类似于临时的视图这么一个东西 
    where是从这个临时的视图中筛选数据的 
    所以,你首先要搞清,你的所谓的2个条件属于哪一种 
    
    
    
    
    Delete 
    
    
    
    
    delete 语句也是类似 
    
    delete from t1 from t1 inner join t2 on t1.id = t2.tid 
    
    注意蓝色部分。 
    
    mysql: 
    
    
    Sql代码 
    DELETE mwb FROM  mem_world_building AS mwb INNER JOIN mem_world AS mw   
    ON mwb.wid = mw.wid   
    where mw.type between 11 and 15    
    and baseid = 107    
    and mw.parentid <> 0    
    and  mw.size > 1;  
    
    DELETE mwb FROM  mem_world_building AS mwb INNER JOIN mem_world AS mw 
    ON mwb.wid = mw.wid 
    where mw.type between 11 and 15 
    and baseid = 107 
    and mw.parentid <> 0 
    and  mw.size > 1;  
    下面是ORACLE的: 
    
    
    Sql代码 
    DELETE TABLE1 where exists ( select 1 from table2 where and table1.khid=table2.khid and FWDWID=8);  
    
    DELETE TABLE1 where exists ( select 1 from table2 where and table1.khid=table2.khid and FWDWID=8); 
    
    
    
    Sql代码 
    DELETE TABLE1 where KHID exists ( select KHID from table2 where FWDWID=8)  
    
    DELETE TABLE1 where KHID exists ( select KHID from table2 where FWDWID=8)
    View Code
  • 相关阅读:
    【高斯消元】BZOJ 1770: [Usaco2009 Nov]lights 燈
    【高斯消元】Poj 1222:EXTENDED LIGHTS OUT
    【高斯消元】BZOJ 1013: [JSOI2008]球形空间产生器sphere
    【数学】[BZOJ 3884] 上帝与集合的正确用法
    【数学/扩展欧几里得/线性求逆元】[Sdoi2008]沙拉公主的困惑
    【数学/扩展欧几里得/Lucas定理】BZOJ 1951 :[Sdoi 2010]古代猪文
    【扩展欧几里得】Bzoj 1407: [Noi2002]Savage
    [51nod2935] 土地划分
    [51nod2982] 大逃杀
    [BZOJ1005] HNOI2008 明明的烦恼
  • 原文地址:https://www.cnblogs.com/cs_net/p/2408996.html
Copyright © 2020-2023  润新知