/* D - Nineteen Time Limit:1000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u Submit Status Practice CodeForces 393A Description Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string. For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters. Help her to find the maximum number of "nineteen"s that she can get in her string. Input The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100. Output Print a single integer — the maximum number of "nineteen"s that she can get in her string. Sample Input Input nniinneetteeeenn Output 2 Input nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii Output 2 Input nineteenineteen Output 2 By Grant Yuan 2014.7.11*/ #include<iostream> #include<stdio.h> #include<stdlib.h> #include<string.h> using namespace std; char a[102]; char b[4]={'n','i','e','t'}; int c[4]; int main() { memset(c,0,sizeof(c)); cin>>a; int l,t; l=strlen(a); //cout<<l<<endl; for(int i=0;i<l;i++) for(int j=0;j<4;j++) if(a[i]==b[j]) c[j]++; //c[0]=c[0]/3; c[2]=c[2]/3; int min=c[0]; for(int i=0;i<4;i++) if(c[i]<min) min=c[i]; /* if(min==1) if(c[0]<3) min=0; else {if(min>1) //if(c[0]<3+(min-1)) t=(c[0]-3)/2; if(t<min) min=t;}*/ int j; if(min>0) if(c[0]<1+2*min){ for(j=min;j>0;j--) {if(c[0]>=1+2*j) break;} min=j;} cout<<min<<endl; return 0; }