• P4012 深海机器人问题


    网络流24题之一,拆点加拆边。洛谷上有许多题解,这里就不班门弄斧啦。

    #include<iostream>
    #include<cstdio>
    #include<queue>
    #include<cstring>
    using namespace std;
    const int N=5000+10;
    const int M=50000+10;
    const int INF=0x3f3f3f3f;
    int n,m,s,t,A,B,bs,maxflow,mincost;
    struct edge{
        int nxt,to,cap,cost;
    }edges[M<<1];
    int cnt=1,head[N],pre[N];
    
    void add_edge(int x,int y,int z,int c) {
        edges[++cnt].nxt=head[x]; edges[cnt].to=y; edges[cnt].cap=z; edges[cnt].cost=c; head[x]=cnt;
    }
    
    queue<int> q;
    int dis[N],lim[N]; 
    bool inq[N];
    bool spfa(int s,int t) {
        while (!q.empty()) q.pop();
        memset(dis,0x3f,sizeof(dis));
        memset(inq,0,sizeof(inq));
        dis[s]=0; inq[s]=1; lim[s]=INF; q.push(s);
        while (!q.empty()) {
            int x=q.front(); q.pop();
            for (int i=head[x];i;i=edges[i].nxt) {
                edge e=edges[i];
                if (e.cap && dis[x]+e.cost<dis[e.to]) {
                    dis[e.to]=dis[x]+e.cost;
                    pre[e.to]=i;  //即e.to这个点是从i这条边来的 
                    lim[e.to]=min(lim[x],e.cap);
                    if (!inq[e.to]) { q.push(e.to); inq[e.to]=1; }
                }
            }
            inq[x]=0;
        }
        return !(dis[t]==INF); 
    }
    
    void MCMF() {
        maxflow=0; mincost=0;
        while (spfa(s,t)) {
            int now=t;
            maxflow+=lim[t];
            mincost+=lim[t]*dis[t];
            while (now!=s) {
                edges[pre[now]].cap-=lim[t];
                edges[pre[now]^1].cap+=lim[t];
                now=edges[pre[now]^1].to;
            }
        }
    }
    
    int id(int x,int y) { return (x-1)*m+y; }
    
    int main()
    {
        scanf("%d%d%d%d",&A,&B,&n,&m); n++; m++;
        s=0; t=2*n*m+1; bs=n*m;
        for (int i=1;i<=n;i++) {
            for (int j=1;j<m;j++) {
                int x; scanf("%d",&x);
                add_edge(id(i,j)+bs,id(i,j+1),1,-x);
                add_edge(id(i,j+1),id(i,j)+bs,0,x);
                add_edge(id(i,j)+bs,id(i,j+1),INF,0);
                add_edge(id(i,j+1),id(i,j)+bs,0,0);
            }
        }
        for (int j=1;j<=m;j++) {
            for (int i=1;i<n;i++) {
                int x; scanf("%d",&x);
                add_edge(id(i,j)+bs,id(i+1,j),1,-x);
                add_edge(id(i+1,j),id(i,j)+bs,0,x);
                add_edge(id(i,j)+bs,id(i+1,j),INF,0);
                add_edge(id(i+1,j),id(i,j)+bs,0,0);
            }
        }
        for (int i=1;i<=n;i++) for (int j=1;j<=m;j++) 
            add_edge(id(i,j),id(i,j)+bs,INF,0),add_edge(id(i,j)+bs,id(i,j),0,0);
        for (int i=1;i<=A;i++) {
            int k,x,y; scanf("%d%d%d",&k,&x,&y); x++; y++;
            add_edge(s,id(x,y),k,0);
            add_edge(id(x,y),s,0,0);
        }
        for (int i=1;i<=B;i++) {
            int k,x,y; scanf("%d%d%d",&k,&x,&y); x++; y++;
            add_edge(id(x,y)+bs,t,k,0);
            add_edge(t,id(x,y)+bs,0,0);
        }
        
        MCMF();
        cout<<-mincost<<endl;
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/clno1/p/10718985.html
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