• Bzoj5251: [2018多省省队联测]劈配


    题面

    传送门

    Sol

    网络流辣

    枚举每个点的最优匹配,然后只建最优匹配的边跑网络流
    下一个点的图中,保证上一个点只连了最优匹配的边
    直接整个图复制过来

    然后二分答案一个点向上跳多少
    和上面一样建图(check)

    # include <bits/stdc++.h>
    # define RG register
    # define IL inline
    # define Fill(a, b) memset(a, b, sizeof(a))
    # define Copy(a, b) memcpy(a, b, sizeof(a))
    # define File(a) freopen(a".in", "r", stdin), freopen(a".out", "w", stdout)
    using namespace std;
    typedef long long ll;
    
    template <class Int>
    IL void Input(RG Int &x){
    	RG int z = 1; RG char c = getchar(); x = 0;
    	for(; c < '0' || c > '9'; c = getchar()) z = c == '-' ? -1 : 1;
    	for(; c >= '0' && c <= '9'; c = getchar()) x = (x << 1) + (x << 3) + (c ^ 48);
    	x *= z;
    }
    
    const int maxn(405);
    const int oo(1e9);
    
    int testcase, c, n, m, b[maxn], s[maxn], S, T, ans[maxn];
    queue <int> Q;
    
    struct Max_Flow{
    	int max_flow, cur[maxn], first[maxn], cnt, lev[maxn];
    
    	struct Edge{
    		int to, f, next;
    	} edge[maxn * 20];
    
    	IL void Init(){
    		cnt = 0, Fill(first, -1);
    	}
    
    	IL void Add(RG int u, RG int v, RG int f){
    		edge[cnt] = (Edge){v, f, first[u]}, first[u] = cnt++;
    		edge[cnt] = (Edge){u, 0, first[v]}, first[v] = cnt++;
    	}
    
    	IL int Dfs(RG int u, RG int maxf){
    		if(u == T) return maxf;
    		RG int ret = 0;
    		for(RG int &e = cur[u]; e != -1; e = edge[e].next){
    			RG int v = edge[e].to;
    			if(lev[v] != lev[u] + 1 || !edge[e].f) continue;
    			RG int f = Dfs(v, min(edge[e].f, maxf - ret));
    			ret += f, edge[e].f -= f, edge[e ^ 1].f += f;
    			if(ret == maxf) break;
    		}
    		if(!ret) lev[u] = 0;
    		return ret;
    	}
    	
    	IL int Bfs(){
    		Fill(lev, 0), Q.push(S), lev[S] = 1;
    		while(!Q.empty()){
    			RG int u = Q.front(); Q.pop();
    			for(RG int e = first[u]; e != -1; e = edge[e].next){
    				RG int v = edge[e].to;
    				if(!edge[e].f || lev[v]) continue;
    				lev[v] = lev[u] + 1;
    				Q.push(v);
    			}
    		}
    		return lev[T];
    	}
    	
    	IL int Dinic(){
    		max_flow = 0;
    		while(Bfs()) Copy(cur, first), max_flow += Dfs(S, oo);
    		return max_flow;
    	}
    } mp[maxn], tmp;
    
    struct Map{
    	int first[maxn], cnt;
    
    	struct Edge{
    		int to, next;
    	} edge[maxn * 10];
    
    	IL void Init(){
    		cnt = 0, Fill(first, -1);
    	}
    
    	IL void Add(RG int u, RG int v){
    		edge[cnt] = (Edge){v, first[u]}, first[u] = cnt++;
    	}
    } edge[maxn];
    
    int main(RG int argc, RG char *argv[]){
    	File("mentor");
    	for(Input(testcase), Input(c); testcase; --testcase){
    		Input(n), Input(m), T = n + m + 1;
    		for(RG int i = 0; i <= n; ++i) mp[i].Init(), ans[i] = 0;
    		for(RG int i = 1; i <= m; ++i) Input(b[i]), mp[0].Add(i + n, T, b[i]);
    		for(RG int i = 1; i <= m; ++i) edge[i].Init();
    		for(RG int i = 1; i <= n; ++i){
    			for(RG int j = 1, x; j <= m; ++j){
    				Input(x);
    				if(x) edge[x].Add(i, j + n);
    			}
    			for(RG int j = 1; j <= m; ++j){
    				for(RG int k = S; k <= T; ++k) mp[i].first[k] = mp[i - 1].first[k];
    				mp[i].cnt = mp[i - 1].cnt;
    				for(RG int k = 0; k < mp[i].cnt; ++k) mp[i].edge[k] = mp[i - 1].edge[k];
    				mp[i].Add(S, i, 1);
    				for(RG int e = edge[j].first[i]; e != -1; e = edge[j].edge[e].next)
    					mp[i].Add(i, edge[j].edge[e].to, 1);
    				if(mp[i].Dinic()){
    					ans[i] = j;
    					break;
    				}
    			}
    			if(!ans[i]) ans[i] = m + 1;
    			printf("%d ", ans[i]);
    		}
    		puts("");
    		for(RG int i = 1; i <= n; ++i) Input(s[i]);
    		for(RG int i = 1; i <= n; ++i){
    			if(ans[i] <= s[i]){
    				putchar('0'), putchar(' ');
    				continue;
    			}
    			RG int l = 1, r = i - 1, ret = 0;
    			while(l <= r){
    				RG int mid = (l + r) >> 1;
    				for(RG int k = S; k <= T; ++k) tmp.first[k] = mp[mid - 1].first[k];
    				tmp.cnt = mp[mid - 1].cnt;
    				for(RG int k = 0; k < mp[mid - 1].cnt; ++k) tmp.edge[k] = mp[mid - 1].edge[k];
    				tmp.Add(S, i, 1);
    				for(RG int j = 1; j <= s[i]; ++j)
    					for(RG int e = edge[j].first[i]; e != -1; e = edge[j].edge[e].next)
    						tmp.Add(i, edge[j].edge[e].to, 1);
    				if(tmp.Dinic()) ret = mid, l = mid + 1;
    				else r = mid - 1;
    			}
    			printf("%d ", i - ret);
    		}
    		puts("");
    	}
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/cjoieryl/p/8761198.html
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