1 import java.util.Comparator; 2 3 public class MyUtil { 4 5 public static <T extends Comparable<T>> int binarySearch(T[] x, T key) { 6 return binarySearch(x, 0, x.length- 1, key); 7 } 8 9 // 使用循环实现的二分查找 10 public static <T> int binarySearch(T[] x, T key, Comparator<T> comp) { 11 int low = 0; 12 int high = x.length - 1; 13 while (low <= high) { 14 int mid = (low + high) >>> 1; 15 int cmp = comp.compare(x[mid], key); 16 if (cmp < 0) { 17 low= mid + 1; 18 } 19 else if (cmp > 0) { 20 high= mid - 1; 21 } 22 else { 23 return mid; 24 } 25 } 26 return -1; 27 } 28 29 // 使用递归实现的二分查找 30 private static<T extends Comparable<T>> int binarySearch(T[] x, int low, int high, T key) { 31 if(low <= high) { 32 int mid = low + ((high -low) >> 1); 33 if(key.compareTo(x[mid])== 0) { 34 return mid; 35 } 36 else if(key.compareTo(x[mid])< 0) { 37 return binarySearch(x,low, mid - 1, key); 38 } 39 else { 40 return binarySearch(x,mid + 1, high, key); 41 } 42 } 43 return -1; 44 } 45 }
上面的代码中给出了折半查找的两个版本,一个用递归实现,一个用循环实现。需要注意的是计算中间位置时不应该使用(high+ low) / 2的方式,因为加法运算可能导致整数越界,这里应该使用以下三种方式之一:low + (high - low) / 2或low + (high – low) >> 1或(low + high) >>> 1(>>>是逻辑右移,是不带符号位的右移)
转自:https://blog.csdn.net/jackfrued/article/details/44921941