• Kuan滤波C++实现(结合opencv)


    void Kuan(Mat &src, Mat &dst,int n)
    {
        
        
        for( int i = (n-1)/2; i < src.rows-(n-1)/2; ++i)
           for( int j = (n-1)/2; j < src.cols-(n-1)/2 ; ++j )
              {
                  int temp=(src.at<uchar>(i,j)+src.at<uchar>(i-1,j-1)+src.at<uchar>(i-1,j)+src.at<uchar>(i,j-1)
                      +src.at<uchar>(i+1,j)+src.at<uchar>(i,j+1)+src.at<uchar>(i+1,j+1)+src.at<uchar>(i-1,j+1)+src.at<uchar>(i+1,j-1))/9;
                  
                  int temp_devation=sqrt((double) ((src.at<uchar>(i,j)-k)*(src.at<uchar>(i,j)-k)
                                     +(src.at<uchar>(i-1,j-1)-k)*(src.at<uchar>(i-1,j-1)-k)
                                     +(src.at<uchar>(i-1,j)-k)*(src.at<uchar>(i-1,j)-k)
    
                                     +(src.at<uchar>(i,j-1)-k)*(src.at<uchar>(i,j-1)-k)
                                     +(src.at<uchar>(i+1,j)-k)*(src.at<uchar>(i+1,j)-k)
                                     +(src.at<uchar>(i,j+1)-k)*(src.at<uchar>(i,j+1)-k)
    
                                     +(src.at<uchar>(i+1,j+1)-k)*(src.at<uchar>(i+1,j+1)-k)
                                     +(src.at<uchar>(i-1,j+1)-k)*(src.at<uchar>(i-1,j+1)-k)
                                     +(src.at<uchar>(i+1,j-1)-k)*(src.at<uchar>(i+1,j-1)-k))/9);
                 
                  double w=(double)(d*d)/(d*d+temp_devation*temp_devation);
                
                
                   dst.at<uchar>(i,j)=temp+w*(k-temp);
                
              }
    
    
    
    
    }
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  • 原文地址:https://www.cnblogs.com/chchche/p/2815305.html
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