HDU 2069 Coin Change （经典DP）

Coin Change

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 14500    Accepted Submission(s): 4879

Problem Description

Suppose there are 5 types of coins: 50-cent, 25-cent, 10-cent, 5-cent, and 1-cent. We want to make changes with these coins for a given amount of money.

For example, if we have 11 cents, then we can make changes with one 10-cent coin and one 1-cent coin, or two 5-cent coins and one 1-cent coin, or one 5-cent coin and six 1-cent coins, or eleven 1-cent coins. So there are four ways of making changes for 11 cents with the above coins. Note that we count that there is one way of making change for zero cent.

Write a program to find the total number of different ways of making changes for any amount of money in cents. Your program should be able to handle up to 100 coins.

 

Input

The input file contains any number of lines, each one consisting of a number ( ≤250 ) for the amount of money in cents.

 

Output

For each input line, output a line containing the number of different ways of making changes with the above 5 types of coins.

 

Sample Input

11

26

 

Sample Output

4

13

题意：有1,5,10,25,50这五种硬币，给出一个数N,求用这些硬币能组成N的方法有几种。

 

分析：这题数据比较水，用暴力法能过，但是我尝试了很多方式的DP，WA或者超时，还在研究中。。。。

#include <stdio.h>
#include <algorithm>
#include <string.h>
using namespace std;
int main()
{
    int n,a,b,c,d,e,count;
    while(~scanf("%d",&n))
    {
        count=0;
        for(a=0;a<=n;a++)
        {
            for(b=0;5*b<=n-a;b++)
            {
                for(c=0;10*c<=n-a-5*b;c++)
                {
                    for(d=0;25*d<=n-a-5*b-10*c;d++)
                    {
                        e=n-a-5*b-10*c-25*d;
                        if(e%50==0 && a+b+c+d+e/50<=100)
                            count++;
                    }
                }
            }
        }
        printf("%d
",count);
    }
    return 0;
}