• poj-2234 Matches Game


    http://poj.org/problem?id=2234

    Matches Game
    Time Limit: 1000MS   Memory Limit: 65536K
    Total Submissions: 7914   Accepted: 4554

    Description

    Here is a simple game. In this game, there are several piles of matches and two players. The two player play in turn. In each turn, one can choose a pile and take away arbitrary number of matches from the pile (Of course the number of matches, which is taken away, cannot be zero and cannot be larger than the number of matches in the chosen pile). If after a player’s turn, there is no match left, the player is the winner. Suppose that the two players are all very clear. Your job is to tell whether the player who plays first can win the game or not.

    Input

    The input consists of several lines, and in each line there is a test case. At the beginning of a line, there is an integer M (1 <= M <=20), which is the number of piles. Then comes M positive integers, which are not larger than 10000000. These M integers represent the number of matches in each pile.

    Output

    For each test case, output "Yes" in a single line, if the player who play first will win, otherwise output "No".

    Sample Input

    2 45 45
    3 3 6 9
    

    Sample Output

    No
    Yes
     1 #include<stdio.h>
     2 int main()
     3 {
     4     int   n,i,a[50];
     5     int temp,ans;
     6       while(~scanf("%d",&n))
     7       {
     8         temp=0;
     9         ans=-1;
    10         for(i=0;i<n;i++)
    11         {
    12             scanf("%d",&a[i]);
    13             if(i==0)
    14                 ans=a[i];
    15             else
    16                 ans=ans^a[i];
    17             if(a[i]>1)
    18                  temp=1;
    19         }
    20         if(temp==0)
    21         {
    22             if(n%2==1)
    23               printf("No
    ");
    24             else
    25               printf("Yes
    ");
    26         }
    27         else
    28         {
    29             if(ans==0)
    30               printf("No
    ");
    31             else
    32               printf("Yes
    ");
    33             
    34         }
    35     }
    36     return 0;
    37 }
  • 相关阅读:
    bzoj-4433 小凸玩矩阵(二分图,二分+匈牙利)
    HDU-2255 奔小康赚大钱(二分图、km算法、模板)
    python queue和生产者和消费者模型
    python Events
    python递归锁与信号量
    python 线程锁
    python GIL锁
    python 守护进程
    python 继承式多线程
    python 多线程效果演示
  • 原文地址:https://www.cnblogs.com/cancangood/p/3514454.html
Copyright © 2020-2023  润新知