[Aizu] ITP2_10_A~B: Bit Operation

前言

ITP系列之位运算, 具体内容参见bitset

题目链接

ITP2_10_A: Bit Operation I
ITP2_10_B: Bit Operation II

求解

第一题

第一次代码

// file name: 逻辑操作1: 32bit值, 按位取反, 左移, 右移
// Written by: by_sknight
// Date: 2019/6/13
 
#include <bits/stdc++.h>
using namespace std;
 
string bits_of(unsigned int x) {
    string str;
    char ch;
    for (int i = 0; i < 32; i++) {
        ch = (x / (int)pow(2, 31 - i)) % 2 + '0';
        str += ch;
    }
    return str;
}
 
int main(void) {
    ios::sync_with_stdio(false);
    cin.tie(0);
 
    unsigned int x; cin >> x;
    cout << bits_of(x) << endl;
    cout << bits_of(pow(2, 32) - 1 - x) << endl;
    cout << bits_of(x * 2) << endl;
    cout << bits_of(x / 2) << endl;
}

第二次代码

// file name: 逻辑操作1: 32bit值, 按位取反, 左移, 右移
// Written by: by_sknight
// Date: 2019/6/13
 
#include <bits/stdc++.h>
using namespace std;
 
int main(void) {
    ios::sync_with_stdio(false);
    cin.tie(0);
 
    unsigned int x; cin >> x;
    bitset<32> b1(x), b2, b3, b4;
    cout << b1 << endl;
    b2 = b1;
    b2.flip();
    cout << b2 << endl;
    b3 = b1 << 1;
    cout << b3 << endl;
    b4 = b1 >> 1;
    cout << b4 << endl;
}

别人的代码

3160717 Solution for ITP2_10_A by c7c7

#include <bits/stdc++.h>
#define int long long
using namespace std;
main(){
  int x;
  cin>>x;
  bitset<32>b(x);
  cout<<b<<endl;
  cout<<(~b)<<endl;
  cout<<(b<<1)<<endl;
  cout<<(b>>1)<<endl;
}

第二题

第一次代码

// file name: 逻辑操作1: 32bit值, 按位取反, 左移, 右移
// Written by: by_sknight
// Date: 2019/6/13
 
#include <bits/stdc++.h>
using namespace std;
 
string bits_of(unsigned int x) {
    string str;
    char ch;
    for (int i = 0; i < 32; i++) {
        ch = (x / (int)pow(2, 31 - i)) % 2 + '0';
        str += ch;
    }
    return str;
}
 
int main(void) {
    ios::sync_with_stdio(false);
    cin.tie(0);
 
    unsigned int a, b; cin >> a >> b;
    cout << bits_of(a & b) << endl;
    cout << bits_of(a | b) << endl;
    cout << bits_of(a ^ b) << endl;
}

提交的时候忘记了修改最前面的描述了

第二次代码

// file name: 逻辑操作2: 两个数按位与,或,非
// Written by: by_sknight
// Date: 2019/6/13
 
#include <bits/stdc++.h>
using namespace std;
 
int main(void) {
    ios::sync_with_stdio(false);
    cin.tie(0);
 
    unsigned int a, b; cin >> a >> b;
    bitset<32> bs_a(a), bs_b(b), bs;
    bs = bs_a & bs_b;
    cout << bs << endl;
    bs = bs_a | bs_b;
    cout << bs << endl;
    bs = bs_a ^ bs_b;
    cout << bs << endl;
}

别人的代码

#include <bits/stdc++.h>
#define int long long
using namespace std;
main(){
  int x,y;
  cin>>x>>y;
  bitset<32>a(y),b(x);
  //cout<<b<<endl;
  //cout<<(~b)<<endl;
  //cout<<(b<<1)<<endl;
  //cout<<(b>>1)<<endl;
  cout<<(a&b)<<endl;
  cout<<(a|b)<<endl;
  cout<<(a^b)<<endl;
}

总结

基础的位运算符掌握的不够到位, 代码不够整洁