• MSSQL 合并拆分表


    --合并分拆表
    /******************************************************************************************************************************************************
    合并分拆表数据
    
    整理人:中国风(Roy)
    
    日期:2008.06.06
    ******************************************************************************************************************************************************/
    
    --> --> (Roy)生成測試數據
     
    if not object_id('Tab') is null
    	drop table Tab
    Go
    Create table Tab([Col1] int,[Col2] nvarchar(1))
    Insert Tab
    select 1,N'a' union all
    select 1,N'b' union all
    select 1,N'c' union all
    select 2,N'd' union all
    select 2,N'e' union all
    select 3,N'f'
    Go
    
    合并表:
    
    SQL2000用函数:
    
    go
    if object_id('F_Str') is not null
    	drop function F_Str
    go
    create function F_Str(@Col1 int)
    returns nvarchar(100)
    as
    begin
    	declare @S nvarchar(100)
    	select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1
    	return @S
    end
    go
    Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab
    
    go
    
    SQL2005用XML:
    
    方法1:
    
    select 
    	a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'')
    from 
    	(select distinct COl1 from Tab) a
    Cross apply
    	(select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b
    
    方法2:
    
    select 
    	a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44))
    from 
    	(select distinct COl1 from Tab) a
    cross apply
    	(select Col2=(select COl2 from Tab  where COl1=a.COl1 FOR XML AUTO, TYPE)
    				.query('<Tab>
    				{for $i in /Tab[position()<last()]/@COl2 return concat(string($i),",")}
    				{concat("",string(/Tab[last()]/@COl2))}
    				</Tab>')
    				)b
    
    SQL05用CTE:
    
    ;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab)
    ,Roy2 as
    (select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1 
    union all 
    select a.Col1,cast(b.COl2+','+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1)
    select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0)
    
    
    生成结果:
    /*
    Col1        COl2
    ----------- ------------
    1           a,b,c
    2           d,e
    3           f
    
    (3 行受影响)
    */
    
    
    拆分表:
    
    --> --> (Roy)生成測試數據
     
    if not object_id('Tab') is null
    	drop table Tab
    Go
    Create table Tab([Col1] int,[COl2] nvarchar(5))
    Insert Tab
    select 1,N'a,b,c' union all
    select 2,N'd,e' union all
    select 3,N'f'
    Go
    
    SQL2000用辅助表:
    if object_id('Tempdb..#Num') is not null
    	drop table #Num
    go
    select top 100 ID=Identity(int,1,1) into #Num from syscolumns a,syscolumns b
    Select 
    	a.Col1,COl2=substring(a.Col2,b.ID,charindex(',',a.Col2+',',b.ID)-b.ID) 
    from 
    	Tab a,#Num b
    where
    	charindex(',',','+a.Col2,b.ID)=b.ID --也可用 substring(','+a.COl2,b.ID,1)=','
    
    
    SQL2005用Xml:
    
    select 
    	a.COl1,b.Col2
    from 
    	(select Col1,COl2=convert(xml,'<root><v>'+replace(COl2,',','</v><v>')+'</v></root>') from Tab)a
    outer apply
    	(select Col2=C.v.value('.','nvarchar(100)') from a.COl2.nodes('/root/v')C(v))b
    
    
    
    
    SQL05用CTE:
    
    ;with roy as 
    (select Col1,COl2=cast(left(Col2,charindex(',',Col2+',')-1) as nvarchar(100)),Split=cast(stuff(COl2+',',1,charindex(',',Col2+','),'') as nvarchar(100)) from Tab
    union all
    select Col1,COl2=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from Roy where split>''
    )
    select COl1,COl2 from roy order by COl1 option (MAXRECURSION 0)
    
    生成结果:
    /*
    Col1        COl2
    ----------- -----
    1           a
    1           b
    1           c
    2           d
    2           e
    3           f
    */
    

      

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  • 原文地址:https://www.cnblogs.com/blackice/p/2870559.html
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