• BZOJ1787/Luogu4281: [Ahoi2008]Meet 紧急集合


    画画图可知,三点(lca)必有两相同,(a,b,c)距离为(dis_a + dis_b + dis_c - dis_{lca(a,b)} - dis_{lca(b,c)} - dis_{lca(a,c)})

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #define R(a,b,c) for(register int  a = (b); a <= (c); ++ a)
    #define nR(a,b,c) for(register int  a = (b); a >= (c); -- a)
    #define Max(a,b) ((a) > (b) ? (a) : (b))
    #define Min(a,b) ((a) < (b) ? (a) : (b))
    #define Fill(a,b) memset(a, b, sizeof(a))
    #define Swap(a,b) a^=b^=a^=b
    #define ll long long
    #define ON_DEBUG
    
    #ifdef ON_DEBUG
    
    #define D_e_Line printf("
    
    ----------
    
    ")
    #define D_e(x)  cout << #x << " = " << x << endl
    #define Pause() system("pause")
    
    #else
    
    #define D_e_Line ;
    
    #endif
    
    struct ios{
        template<typename ATP>ios& operator >> (ATP &x){
            x = 0; int f = 1; char c;
            for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-')  f = -1;
            while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
            x*= f;
            return *this;
        }
    }io;
    using namespace std;
    
    const int N = 500007;
    
    struct Edge{
    	int nxt, pre, w;
    }e[N << 1];
    int head[N], cntEdge;
    inline void add(int u, int v, int w){
    	e[++cntEdge] = (Edge){head[u], v, w}, head[u] = cntEdge;
    }
    
    int dis[N];
    int fa[N], son[N], siz[N], dep[N];
    inline void DFS_First(int u, int father){
    	fa[u] = father, dep[u] = dep[father] + 1, siz[u] = 1;
    	for(register int i = head[u]; i; i = e[i].nxt){
    		int v = e[i].pre;
    		if(v == father) continue;
    		dis[v] = dis[u] + e[i].w;
    		DFS_First(v, u);
    		siz[u] += siz[v];
    		if(!son[u] || siz[v] > siz[son[u]]){
    			son[u] = v;
    		}
    	}
    }
    int dfn[N], dfnIdx, top[N];
    inline void DFS_Second(int u, int ancester){
    	top[u] = ancester, dfn[u] = ++dfnIdx;
    	if(!son[u]) return;
    	DFS_Second(son[u], ancester);
    	for(register int i = head[u]; i; i = e[i].nxt){
    		int v = e[i].pre;
    		if(v != son[u] && v != fa[u]){
    			DFS_Second(v, v);
    		}
    	}
    }
    inline int LCA(int x, int y){
    	while(top[x] != top[y]){
    		if(dep[top[x]] < dep[top[y]]) Swap(x, y);
    		x = fa[top[x]];
    	}
    	return dep[x] < dep[y] ? x : y;
    }
    
    int main(){
    	int n, Ques;
    	io >> n >> Ques;
    	R(i,2,n){
    		int u, v;
    		io >> u >> v;
    		add(u, v, 1);
    		add(v, u, 1);
    	}
    	
    	DFS_First(1, 0);
    	DFS_Second(1, 1);
    	
    	while(Ques--){
    		int a, b, c;
    		io >> a >> b >> c;
    		int A = LCA(a, b), B = LCA(b, c), C = LCA(a, c);
    //		int disA = dis[a] + dis[b] - (dis[A] << 1);
    //		int disB = dis[b] + dis[c] - (dis[B] << 1);
    //		int disC = dis[a] + dis[c] - (dis[C] << 1);
    		int pos;
    		if(A == B) pos = C;
    		else if(B == C) pos = A;
    		else pos = B;
    		printf("%d %d
    ", pos, dis[a] + dis[b] + dis[c] - dis[A] - dis[B] - dis[C]);
    	}
    	
    	return 0;
    }
    

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  • 原文地址:https://www.cnblogs.com/bingoyes/p/11218046.html
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